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Sonja [21]
3 years ago
8

several students in Ashton 's class were randomly selected and asked how many text messages they sent yesterday. Their answers w

ere 1 ,0 ,10 , 7 , 13, 2 , 9 ,15 ,0 , 3 .find the mean and the median for this data .
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
7 0
Mean: 6 ADD up all the numbers and then divide by 10. SO 60÷10=6. 
 Median: 5  Put them in order and find the middle number. In this case 3 and 7 are in the middle. SO add them up and divide by 2.     3 + 7 =10.
rosijanka [135]3 years ago
3 0
Mean is 6 because once you add up all the numbers it will be 60, and dividing that number by how many you have will give you 6

Median is 5 because once you place the numbers in order, 0, 0, 1, 2, 3, 7, 9, 10, 13, 15 the middle number in the set is between 3 and 7 and once you find the mean of the two you get 5
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Answer: volunteer within each block should live in similar environments to each other when it comes to mosquitos

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Orlov [11]
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5 0
3 years ago
for a class gardening project 1/3 of mrs gordon's students planted marigolds and 1/2 planted tulips what fraction of the class p
vladimir2022 [97]
Get them to have a common denominator so you can add them
(1/3)×2= 2/6 and (1/2)×3= 3/6
Add them together
(2/6)+ (3/6)= 5/6
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5 0
3 years ago
-3x+10=34 solve for x
goblinko [34]
<h3>Answer:</h3><h3>x=−8</h3><h3 />

Step-by-step explanation:

<h3>Let's solve your equation step-by-step.</h3>

−3x+10=34

<h3>Step 1: Subtract 10 from both sides.</h3>

−3x+10−10=34−10

−3x=24

<h3>Step 2: Divide both sides by -3.</h3><h3 />

−3x/−3 = 24/−3

<h3>x=−8</h3>
5 0
3 years ago
Read 2 more answers
7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con
sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let p_{1} be the probability that commercial cars have rear license plates and p_{2} be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

H_{0}:p_{1} =p_{2}

H_{1} :p_{1} < p_{2}

It is a left tailed test at 0.05 significance.

Standard errors of p=\sqrt{p(1-p)/n}

=\sqrt{(0.1191*0.8809)/2383}

=\sqrt{0.1049/2383}        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0
2 years ago
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