Question

A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?

Answer 1

Answer:

The area of the doghouse is $66.5\ ft^{2}$

Step-by-step explanation:

we know that

The area of trapezoid is equal to

$A=\frac{1}{2}(b1+b2)h$

where

b1,b2 are the parallel bases of trapezoid

h is the height of trapezoid

in this problem we have

$b1=7\ ft$

$b2=7+5=12\ ft$

$h=7\ ft$

substitute

$A=\frac{1}{2}(7+12)7=66.5\ ft^{2}$

Answer 2

First we will find the total measure of the second base.

Second base is extended more so that meas it will measure extended part plus the first base.

Second base = 7 + 5 = 12.

Now for the area.

A = 1/2(b1+b2)(h)
A = 1/2(7 + 12)(7)
A = 66.5

The area is 66.5 ft²

Hope this helps :)