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3 years ago

What two consecutive even integers have a sum of -66?

Mathematics

2 answers:

pshichka [43]3 years ago

7 0

Answer:

the sum of 2 consecutive even integers is 66.

Step-by-step explanation:

This means that if one integers is x, the other must be either x-2 or x+2. Therefore, we can write 6=x+(×-2)=2×2. Solving for x, we can find ×=34. this means that the other integer is 34-2=32. indeed, 32+34=66, and done hope this helped C:

DIA [1.3K]3 years ago

4 0

Integers is 66 2 is even

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3 years ago

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denpristay [2]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π → A = π - (B + C)

→ B = π - (A + C)

→ C = π - (A + B)

Use Sum to Product Identity: sin A - sin B = 2 cos [(A + B)/2] · sin [(A - B)/2]

Use the following Cofunction Identity: cos (π/2 - A) = sin A

<u>Proof LHS → RHS:</u>

LHS: sin A - sin B + sin C

= (sin A - sin B) + sin C

$\text{Sum to Product:}\quad 2\cos \bigg(\dfrac{A+B}{2}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)$

$\text{Given:}\qquad 2\cos \bigg(\dfrac{\pi -(B+C)}{2}+\dfrac{B}{2}}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad =2\cos \bigg(\dfrac{\pi -C}{2}\bigg)\cdot \sin \bigg(\dfrac{A-B}{2}\bigg)+2\cos \bigg(\dfrac{C}2{}\bigg)\cdot \sin \bigg(\dfrac{C}{2}\bigg)$

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Step-by-step explanation:

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liberstina [14]

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Step-by-step explanation:

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statuscvo [17]

Answer:

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Step-by-step explanation:

The daily machine productivity refers to the TOTAL production made in a day.

The problem says that a shop produces metal on two different machines. It means that you must take into account the daily production of each one for finding the total production.

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3 years ago