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Evgesh-ka [11]
3 years ago
6

What two consecutive even integers have a sum of -66?

Mathematics
2 answers:
pshichka [43]3 years ago
7 0

Answer:

the sum of 2 consecutive even integers is 66.

Step-by-step explanation:

This means that if one integers is x, the other must be either x-2 or x+2. Therefore, we can write 6=x+(×-2)=2×2. Solving for x, we can find ×=34. this means that the other integer is 34-2=32. indeed, 32+34=66, and done hope this helped C:

DIA [1.3K]3 years ago
4 0
Integers is 66 2 is even
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3 years ago
Factor −14 out of −12x−54y.
uysha [10]

we are given

-12x-54y

Since, we have to factor out -14

So, we will make both terms multiple of -14

so, we will multiply top and bottom of each terms by -14

-12x-54y=\frac{-14}{-14}\times -12x-\frac{-14}{-14}\times 54y

we can also write as

-12x-54y=-14\times \frac{-12x}{-14}-(-14)\times \frac{54y}{-14}

now, we can factor out -14

-12x-54y=-14\times (\frac{-12x}{-14}-\frac{54y}{-14})

now, we can simplify it

-12x-54y=-14\times (\frac{6x}{7}+\frac{27y}{7})..............Answer



5 0
4 years ago
The algebra teacher said if you square my age then subtract 23 times my age, the result is 50. How old is he?
viva [34]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How to solve this equation: ax² - 5x + 2 = 0
swat32

Answer:

x=\frac{5(+/-)\sqrt{25-8a}} {2a}

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

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substitute in the formula

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Answer:

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