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cluponka [151]
3 years ago
8

- 7 - w <10 what is the answer

Mathematics
1 answer:
sesenic [268]3 years ago
3 0
-7-w<10
Add 7 to each side
-w<17
Change signs and flip sign
w>17

Hope this helps :)
You might be interested in
Can someone help me please
vovikov84 [41]
X=7




Explanation:

A triangle equals 180°, and they gave us one length already, and it says the one arm of the triangle is equal to the other so we know that the third angle is going to be the same as the second angle.


180=90+(6x+3)+(6x+3)
Combine like terms
180=96+12x
Subtract 96 from both sides
84=12x
Divide 12 by both sides
7=x


Now check it,

90+(6*7+3)+(6*7+3)
90+(45)+(45) =180
8 0
3 years ago
PLEASE HELP HURRY!!!!!!!
Charra [1.4K]

As it has been given that x=4+5i, y=2-9i.

We need to find the value of the following:

(i) 4x-y, substituting the value of 'x' and 'y' in the expression, we get:

4(4+5i)-(2-9i)=4\times 4+4\times 5i-2+9i=16+20i-2+9i

=14+29i

So, 4x-y=14+29i

(ii) -x+3y, substituting the value of 'x' and 'y' in the expression, we get:

-(4+5i)+3(2-9i)=-4-5i+3\times 2-3 \times 9i=-4-5i+6-27i

=2-32i

So, -x+3y=2-32i

(iii) x \times y, we need to substitute the value of 'x' and 'y' in the expression,  for this, we can use distributive property of multiplication that says,

a(b+c)=a \times b+ a \times c

Using the distributive property of multiplication:

(4+5i)\times(2-9i)=4 \times 2-4 \times 9i+5i \times 2-5i \times 9i

=8-36i+10i-45i^2

Now, we know that i \times i=i^2=-1

We get, 8-36i+10i-45 \times (-1)=8-26i+45

=8+45-26i=53-26i

Therefore, x \times y=53-26i.

(iv) We have, 2x \times y, we need to substitute the value of 'x' and 'y' in the expression, we get:

2(4+5i)\times (2-9i)

Again, we can use distributive property of multiplication that says,

a(b+c)=a \times b+ a \times c

So,

2(4+5i) \times (2-9i)=2\times 4+2 \times 5i\times(2-9i)

=8+10i \times(2-9i)=8\times 2-8 \times 9i+10i \times 2-10i \times 9i

=16-72i+20i-90i^2

since, i^2=-1

we get,

16-72i+20i-90 \times (-1)=16-52i+90

=106-52i

Therefore,

2x \times y=106-52i


7 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E%7B8%7D%2A7x%5E%7B3%7D%20%7D%7B3x%5E%7B6%7D%2A7%20%7D" id="TexFormula1" title="
denis23 [38]

Answer:

a = \dfrac{x^2}{3} \quad \textsf{and} \quad b = \dfrac{x^3}{7}

Step-by-step explanation:

Given expression:

\dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7 }

There are several ways this problem can be approached, and therefore many different answers.  The goal is to reduce the given expression to a simple product of two terms in x, set that to the given form 3a⋅7b then solve for a and b.

\implies \dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7}

Cancel the common factors 3 and 7:

\implies \dfrac{\diagup\!\!\!\!3x^{8} \cdot \diagup\!\!\!\!7x^{3} }{\diagup\!\!\!\!3x^{6} \cdot \diagup\!\!\!\!7}

\implies \dfrac{x^8 \cdot x^3}{x^6}

Separate the fraction:

\implies \dfrac{x^8}{x^6} \cdot  x^3

\textsf{Apply the quotient rule of exponents} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies x^{8-6} \cdot x^3

\implies x^{2} \cdot x^3

Now equate the simplified expression to the given form:

\implies x^{2} \cdot x^3=3a \cdot 7b

Therefore:

\begin{aligned}x^{2} &=3a \:\:   &\textsf{ and }\:\: \quad x^3 &=7b\\ \Rightarrow a & = \dfrac{x^2}{3} & \Rightarrow b & = \dfrac{x^3}{7}\end{aligned}

However, we could also separate them as:

\begin{aligned}x^{3} &=3a \:\:   &\textsf{ and }\:\: \quad x^2 &=7b\\ \Rightarrow a & = \dfrac{x^3}{3} & \Rightarrow b & = \dfrac{x^2}{7}\end{aligned}

Another way of writing them would be to go back a few steps and separate the fraction in x terms differently:

\implies \dfrac{x^8 \cdot x^3}{x^6}=x^8 \cdot \dfrac{x^3}{x^6}=x^8 \cdot x^{-3}

Therefore, this would give us:

\begin{aligned}x^{8} &=3a \:\:   &\textsf{ and }\:\: \quad x^{-3} &=7b\\ \Rightarrow a & = \dfrac{x^8}{3} & \Rightarrow b & = \dfrac{1}{7x^3}\end{aligned}

As the given expression reduces to x⁵, we can separate the x term in any way we like, so long as the coefficient of a is ¹/₃ and the coefficient of b is ¹/₇.  Therefore, there are many possible answers.

7 0
2 years ago
Read 2 more answers
Find an explicit rule for the nth term of the sequence.
REY [17]

9514 1404 393

Answer:

  (a)  an = -4·2^(n-1)

Step-by-step explanation:

The form for the general term is ...

  an = a1·r^(n-1) . . . . . a1 is the first term; r is the common ratio

For a1=-4 and r=-8/-4 = 2, the rule will be ...

  an = -4·2^(n-1)

8 0
3 years ago
Read 2 more answers
During a 90-day monsoon season, daily rainfall can be modeled by sinusoidal functions. A low of 4 inches of rainfall was recorde
Phoenix [80]

Answer:

25.4\,days \leq t \leq 34.6\,days

Step-by-step explanation:

Let consider the following model:

c(t) = A \cdot \sin \left(\frac{2\pi \cdot t}{T}  \right) + \bar c

The average is given by the following formula:

\bar c = \frac{c_{min}+c_{max}}{2}

The maximum value is:

c_{max} = 2 \cdot \bar c - c_{min}

c_{max} = 2\cdot (8\,in) - 4\,in

c_{max} = 12\,in

Amplitude is:

A = 12\,in - 8\,in

A = 4\,in

The sine function has a periodicity of 2\pi, where is minimum is reached at \theta = \frac{3\pi}{2}, when t = 30.  The period of the cycle is:

T = \frac{2\pi}{\frac{3}{2}\pi }\cdot (30)

T = 40

The complete expression is:

c(t) = 8\,in + 4\,in \cdot \sin \left(\frac{2\pi}{40}\cdot t  \right)

The times associated with c = 5\,in are, respectively:

8\,in + 4\,in \cdot \sin \left(\frac{2\pi}{40}\cdot t  \right) = 5\,in

4\,in \cdot \sin \left(\frac{2\pi}{40}\cdot t  \right) = -3\,in

\sin \left(\frac{2\pi}{40}\cdot t  \right) = -0.75

t  = \frac{40}{2\pi}\cdot \sin^{-1} (-0.75)

Instants are, respectively:

t_{1} \approx 25.4\,days

t_{2} \approx 34.6\,days

Period is:

25.4\,days \leq t \leq 34.6\,days

8 0
3 years ago
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