Answer:
The required equation of line is y=-6x-57.
Step-by-step explanation:
The point slope form of a line is
Where m is slope of the line.
It is given that a line that passes through (–9, –3) and has a slope of –6.
Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.
Subtract 3 from both the sides.
Therefore the required equation of line is y=-6x-57.
Answer:
A graph has to be clearly labelled and drawn for clarity and to aid the correct interpretation of the data shown on the graph.
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Let
C----------> the center of a circle
C (-4,5)
A-----------> a point on the circle
A (-9,10)
we know that
the distance between point A and point C is the radius of the circle
A (-9,10) C (-4,5)
d=√[(y2-y1)²+(x2-x1)²]--------> √[(5-10)²+(-4+9)²]
=√[(-5)²+(5)²]------> √[(25)+(25)]---------> √50
d=7.07 units
r=d--------> r=7.07 units
the equation of a circle is
(x+4)²+(y-5)²=50
see the attached figure
the answer is
the radius of a circle is 7.07 units
First you have to get x
5x-21=2x-6
3x=15
x=5
then substitute in any of the equations with x to get the y value:
y=2x-6
y=2(5)-6
y=4
so the answer is choice B
hope this helps !