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dsp73
3 years ago
9

Which describes the slope of this line?

Mathematics
2 answers:
igomit [66]3 years ago
5 0

Answer:

Undefined

Step-by-step explanation:

Irina-Kira [14]3 years ago
3 0
In order to know the slope of a line, you need to determine the y-intercept. In this graph, the line does not have a y-intercept because it does not cross the y-axis. 

Therefore, we cannot determine the slope of this line, making it undefinable. 

Final answer:- A.  <span>undefined slope</span>
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The base of a 13 foot ladder is 5 feet away from the wall. How far up the wall does the ladder reach? A)8 feet B)10 feet C)12 fe
Lisa [10]

You are solving for the height. Use the formula:

c² - b² = a²      in which c = hypotenuse

(13)² - (5)² = a²

Simplify

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√144 = √a²

a = √144

a = √(12 x 12)

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98% of the mules who were surveyed said the stubborness was a good trait. if 343 mules gave this response, how many were surveye
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1/2 -(-1/3 + 2/5) = what is the answer ? thank you for helpings means alot to me
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A consumer products company is formulating a new shampoo and is interested in foam height (in mm). Foam height is approximately
Genrish500 [490]

Answer:

a) 0.057

b) 0.5234

c) 0.4766

Step-by-step explanation:

a)

To find the p-value if the sample average is 185, we first compute the z-score associated to this value, we use the formula

z=\frac{\bar x-\mu}{\sigma/\sqrt N}

where

\bar x=mean\; of\;the \;sample

\mu=mean\; established\; in\; H_0

\sigma=standard \; deviation

N = size of the sample.

So,

z=\frac{185-175}{20/\sqrt {10}}=1.5811

\boxed {z=1.5811}

As the sample suggests that the real mean could be greater than the established in the null hypothesis, then we are interested in the area under the normal curve to the right of  1.5811 and this would be your p-value.

We compute the area of the normal curve for values to the right of  1.5811 either with a table or with a computer and find that this area is equal to 0.0569 = 0.057 rounded to 3 decimals.

So the p-value is  

\boxed {p=0.057}

b)

Since the z-score associated to an α value of 0.05 is 1.64 and the z-score of the alternative hypothesis is 1.5811 which is less than 1.64 (z critical), we cannot reject the null, so we are making a Type II error since 175 is not the true mean.

We can compute the probability of such an error following the next steps:

<u>Step 1 </u>

Compute \bar x_{critical}

1.64=z_{critical}=\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}

\frac{\bar x_{critical}-\mu_0}{\sigma/\sqrt{n}}=\frac{\bar x_{critical}-175}{6.3245}=1.64\Rightarrow \bar x_{critical}=185.3721

So <em>we would make a Type II error if our sample mean is less than 185.3721</em>.  

<u>Step 2</u>

Compute the probability that your sample mean is less than 185.3711  

P(\bar x < 185.3711)=P(z< \frac{185.3711-185}{6.3245})=P(z

So, <em>the probability of making a Type II error is 0.5234 = 52.34% </em>

c)

<em>The power of a hypothesis test is 1 minus the probability of a Type II error</em>. So, the power of the test is

1 - 0.5234 = 0.4766

3 0
3 years ago
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