we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

$\qquad\quad\bull ~{\boxed{\bf{ Sin\theta =\dfrac{Perpendicular}{Hypotenuse}}} }~\bull$

Here,

hypotenuse = 23 feet
$\theta$ = 76°
Value of Sin $\theta$ = 0.97
Perpendicular = ?

$\quad\dashrightarrow\quad \sf { sin\theta =\dfrac{P}{H}}$

$\quad\dashrightarrow\quad \sf { sin76° =\dfrac{P}{23}}$

$\quad\dashrightarrow\quad \sf { 0.97=\dfrac{P}{23}}$

$\quad\dashrightarrow\quad \sf {P = 0.97 \times 23 }$

$\quad\dashrightarrow\quad \sf { P = 22.32}$

‎ㅤ‎ㅤ‎ㅤ~Hence, the distance from the top of the ladder to the ground is 22.32 feet !

$\rule{300pt}{2pt}$

4 0

2 years ago

Can anyone help with this?

Marrrta [24]

3 x 2 and 1/3? The answer is 7.

6 0

3 years ago

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Which point lies on the graph of the finite sequence shown? 5, –1, 6, 0, 7, 1, 8

djyliett [7]

Hello,

$u_{1} =5\\
 u_{2} = u_{1}-6=5-6=-1\\
 u_{3} = u_{2}+7=-1+7=6\\
 u_{4} = u_{3}-6=6-6=0\\
 u_{5} = u_{4}+7=0+7=7\\
 u_{6} = u_{5}-6=7-6=1\\
 u_{7} = u_{6}+7=1+7=8\\
...\\

\boxed{ u_{2n} = u_{2n-1}-6}\\\\

\boxed{ u_{2n+1} = u_{2n}+7}\\

$

7 0

3 years ago

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*Will Give Brainliest Answer Please Help*

Will Give Brainliest Answer Please Help