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liubo4ka [24]
3 years ago
14

What is the slope of this graph? 13 −3 3 −13

Mathematics
2 answers:
Lisa [10]3 years ago
8 0
The answer is for that problem is -3

rosijanka [135]3 years ago
5 0
(0,2) (1,-1)
2+1/0-1
3/-1
-3
The slope of the line is -3
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125% of x is 60. What is x
Lunna [17]

Answer:

Step-by-step explanation:

1.put your percent over a 100 so

125%/100 then put 60 over x

2.then cross multiply 100x60=6000

3.then divide 6000 by 125 which is percent

4.your answer is-48

8 0
3 years ago
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The mean life of a particular brand of light bulb is 1200 hours. if you know that at about 95% of this brand of bulbs will last
Snowcat [4.5K]
<span>204
   First, lookup a standard normal table and see what the z-score is for 0.025 (one half of 100% - 95%) to allow for equal sized tails. You should find that the z-score is 1.96. That means that 95% of the time, the value should be within 1.96 standard deviations of the mean. Now let's calculate the standard deviation. 800 is 800 - 1200 = -400 to the left of the mean of 1200. 1600 is 1600 - 1200 = 400 to the right of the mean of 1200. So we are an equal distance of 400 on both sides of the mean. And we know from the z-score of 1.96, that we're 1.96 standard deviations from the mean. So a little division will give us the standard deviation. Which is: 400 / 1.96 = 204.0816327
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4 0
3 years ago
If f(x)=x^2-11x+18 what are the zeros of the function?
UkoKoshka [18]
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8 0
3 years ago
If a person walks 2.4 miles in 1.5 hours, how far can he walk in 3 hours
rusak2 [61]
 since 1.5 is half of 3.0 all  ouj havr t o do is multiply by 2 2.4*2=4.8 answer
7 0
3 years ago
If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.
galina1969 [7]

Answer:

\frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} is your average rate of change,

Step-by-step explanation:

average rate of change is

\frac{f(a+h)-f(a)}{a+h-a}, by slope formula

simplify this to get \frac{f(a+h)-f(a)}{h}, which is the definition of the derivative as h goes to 0

\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}

simplifying

\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} (your average rate of change)

6 0
3 years ago
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