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scoundrel [369]
3 years ago
6

LAST QUESTION SEND HELP!!!!

Mathematics
2 answers:
Luda [366]3 years ago
8 0
22 is my strongest guess
dangina [55]3 years ago
7 0
The answer is D. because you use Pythagoreans theory and do 12^2+23^2 which equals 673, then you root it and get 26. 
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The diagram shows a circle inside a square 16cm Work out the area of the circle
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A(-5,-4) ——> A’ is a glide reflection where the translation is (x,y)—->(x+6,y), and the line of reflection is y=3. What ar
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Solution:

The Point in the coordinate plane is A(-5,-4).

Perpendicular or shortest Distance from line y=3 that is (-5,3) to point (-5,-4) is

=\sqrt{(-5+5)^2+(3+4)^2}\\\\=7

When it is reflected through the line, y=3, the coordinate of point A (-5,-4) changes to (-5,3+7)= B(-5,10).

Now, the Point B is translated by the rule , (x,y)—->(x+6,y),

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Option C: (1,10) is the glide reflection of point A(-5,-4).

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Answer Question number 5 <br> Plzzzzzz
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Answer:

Step-by-step explanation:

a = -4/3

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nth term = a +(n-1)d

\frac{-4}{3}+(n-1)*\frac{1}{3}=\frac{13}{3}\\\\(n-1)*\frac{1}{3}=\frac{13}{3}-\frac{-4}{3}\\\\(n-1)*\frac{1}{3}=\frac{13+4}{3}\\\\(n-1)*\frac{1}{3}=\frac{17}{3}\\\\n-1=\frac{17}{3}*\frac{3}{1}\\\\n-1=17\\\\n=17+1=18

Middle terms are 9the term and 10th term

t_{9}=\frac{-4}{3}+8*\frac{1}{3}=\frac{-4}{3}+\frac{8}{3}=\frac{4}{3}\\\\t_{10}=\frac{-4}{3}+9*\frac{1}{3}=\frac{-4}{3}+\frac{9}{3}=\frac{5}{3}\\\\ t_{9}+t_{10}=\frac{4}{3}+\frac{5}{3}=\frac{9}{3}=3\\\\t_{9}+t_{10}=3

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A rectangle with sides of lengths 4/5 foot and 1/2 foot
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The area would be .4 cubic feet. The perimeter would be 2.1
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