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andreev551 [17]
3 years ago
13

Consider the rate law below. R=k(NO2)^2 what happens to the rate if the concentration is tripled?

Mathematics
1 answer:
vitfil [10]3 years ago
3 0
For this case we have the following equation:
 R = k (NO2) ^ 2
 if the concentration is tripled, we must rewrite the equation.
 We have then:
 R '= k (3 * NO2) ^ 2
 R '= 9 * k (NO2) ^ 2
 Rewriting:
 R '= 9 * R
 Answer:
 
The rate increases by a factor of 9.
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