What is 10% as a fraction in simplest

Please help!!!! i will give brainliest

FromTheMoon [43]

Answer:

The volume of a cylinder:

$V \approx 150.796$ $ft^3$

Step-by-step explanation:

To find the volume of a cylinder, you need the this formula:

$V = \pi r^2h$

-Use the given height and radius for the formula:

$V = \pi 4^2 3$

-Then, solve the formula:

$V = \pi \times 4^2 \times 3$

$V = \pi \times 16 \times 3$

$V = \pi \times 48$

$V = 48\pi \approx 150.796$

So, the volume of a cylinder is approximately $150.796$ $ft^3$ .

7 0

3 years ago

Suppose it takes 2 1/2 h to drive from your house to the lake at 48 mi/h. How long will your return trip take at 40 mi/h?

Y_Kistochka [10]

Answer

The distance from the house to the lake is (2.5 hr)*(48 mi/hr) = 120 miles. The rerurn trip would take (120 mi)/(40 mi/hr) = 3 hours. Distance equals rate times time, so the distance to the lake is 2 1/2 hours times 48 miles per hour.

I hope this helps

4 0

3 years ago

How could you use coordinate geometry to prove that segment BD and segment AC bisect one another?

____ [38]

Answer:

I think it's prove the midpoints are the same

Step-by-step explanation:

I'm not completely sure but I'm taking it right now and I believe that's the most logical answer because if they meet up at the same midpoint then they could bisect each other.

3 0

3 years ago

The sum of 3 consecutive number multiples of 6 is 162 find thesse numbers

MAXImum [283]

let the numbers are x , x+1 ,x+2

∴ 6 [ x + (x+1) +(x+2) ] = 162

∴ x + (x+1) + (x+2) = 162/6 = 27

∴3x + 3 = 27

∴ 3x = 27 - 3 = 24

∴ x = 24/3 = 8

<u>So, the numbers are 8 , 9 , 10</u>

7 0

4 years ago

A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.

Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

$p(m) = 0.52$ (which corresponds to 52%)

While the probability that the birth is a female can be written as

$p(f) = 0.48$ (which corresponds to 48%)

Here we want to calculate the probability that over 2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

$p(mm)=p(m)\cdot p(m)$

And substituting, we find

$p(mm)=0.52\cdot 0.52 = 0.27$

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

$p(ff)$

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

$p(ff)=p(f)\cdot p(f)$