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4 years ago

7. Does any rectangle rotate onto itself in less than a half-turn?

Mathematics

2 answers:

MAVERICK [17]4 years ago

8 0

Sure. If the rectangle is a square, then
it rotates onto itself in only 1/4 turn.

Galina-37 [17]4 years ago

6 0

I believe so because a full turn is 360 degrees correct so a half turn would be 180 and if you turn the rectangle 90 degrees twice it will be the cover the original rectangle but it would take the full half turn. so it depends on what the want if they mean less and it cant be 180 than the answer is no but if it can be on the half way marker it should be yes

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The length of a postage stamp is

AleksAgata [21]

<h3>Answer: Choice B</h3><h3>2W+2( W+4 1/4) = 124 1/2</h3>

=========================================

Explanation:

L = length

W = width

"The length is 4 1/4 longer than the width" (paraphrase) so

L = W + 4 1/4

This means,

P = perimeter = 124 1/2

P = 2L+2W

2L+2W = P

2W+2L = P

2W+2( L ) = P

2W+2( W+4 1/4) = 124 1/2

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4 years ago

Simplify fully 125y2/10xy

ch4aika [34]

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Answer: 25y/2x

Explanation:

First you need to find the GCF of 125 and 10, which is 5

making it 25y^2/2xy, Then you get rid of 1 of the y's from both of the sides because you don't need them, they cancel eachother out, 25y/2x

I hope this helped!

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ohaa [14]

Answer:

Step-by-step explanation:

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2 years ago

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A chef has 10 spice jars, but his new spice rack only holds 8 spice jars. How many ways can he arrange 8 jars on the spice rack?

aksik [14]

He has 10 spice jars, but the spice rack only holds 8 spice jars.
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$_{10} C _8=\frac{10!}{8!(10-8)!}=\frac{10!}{8! \times 2!}$

Each combination of 8 spice jars that he chooses he can arrange in 8! ways.

He can choose 8 spice jars in (10!)/(8!×2!) ways and arrange each combination in 8! ways.
Using the rule of product:
$8! \times \frac{10!}{8! \times 2!}=\frac{10!}{2!}=\frac{2 \times 3 \times 4 \times 5 \times 6 \times 7 \times 8 \times 9 \times 10}{2}=1814400$

He can arrange 8 jars on the spice rack in c. 1,814,400 ways.

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3 years ago

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