Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span> 6x2 - x - 4 = 0 <span>((2•3x2) - x) - 4 = 0
</span><span>Step 2 :</span>Trying to factor by splitting the middle term
<span> 2.1 </span> Factoring <span> 6x2-x-4</span>
The first term is, <span> <span>6x2</span> </span> its coefficient is <span> 6 </span>.
The middle term is, <span> -x </span> its coefficient is <span> -1 </span>.
The last term, "the constant", is <span> -4 </span>
Step-1 : Multiply the coefficient of the first term by the constant <span> <span> 6</span> • -4 = -24</span>
Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is <span> -1 </span>.
<span><span> -24 + 1 = -23</span><span> -12 + 2 = -10</span><span> -8 + 3 = -5</span><span> -6 + 4 = -2</span><span> -4 + 6 = 2</span><span> -3 + 8 = 5</span><span> -2 + 12 = 10</span><span> -1 + 24 = 23
</span></span>
Observation : No two such factors can be found !!
Conclusion : Trinomial can not be factored
<span>Equation at the end of step 2 :</span><span> 6x2 - x - 4 = 0 </span>
Answer:
111.2
Step-by-step explanation:
The square root and the ^2 cancel each other out so the number stays the same or 111.2
Answer:
See below
Step-by-step explanation:
32. w + 5 = -20
w = -20 - 5
w = - 25
33. x - 17 = -32
x = -32 + 17
x = - 15
34. t + 7.2 = 1.65
t = 1.65 - 7.2
t = - 5.55
35. -0.4 = g - 4.9
g = - 0.4 + 4.9
g = 4.5
36. y - 2/5 = 1 3/5
y = 1 3/5 + 2/5
y = 1 5/5 or 2
37. -5 1/6 = 2 1/3 + p
p = - 5 1/6 - 2 1/3 convert 1/3 to x/6 for a common denominator
1/3 converts to 2/6
p = -5 1/6 - 2 2/6
p = - 7 3/6 or - 7 1/2
38. You were given that
Simone = $65.35 + Dan
Simone = Carly - 37.50
Carly = 127.75
So Simone = 127.75 - 37.50 = 90.25
Simone = 65.35 + Dan or Dan = Simone - 65.35
Dan = 90.25 - 65.35 = 24.90
The probability of getting 3 or more who were involved in a car accident last year is 0.126.
Given 9% of the drivers were involved in a car accident last year.
We have to find the probability of getting 3 or more who were involved in a car accident last year if 14 were selected randomly.
We have to use binomial theorem which is as under:
n
where p is the probability an r is the number of trials.
Probability that 3 or more involved in a car accident last year if 14 are randomly selected=1-[P(X=0)+P(X=1)+P(X=2)]
=1-{
}
=1-{1*0.2670+14!/13!*0.9*0.29+14!/2!12!*0.0081*0.2358}
=1-{0.2670+0.3654+0.2358}
=1-0.8682
=0.1318
Among the options given the nearest is 0.126.
Hence the probability that 3 or more are involved in the accident is 0.126.
Learn more about probability at brainly.com/question/24756209
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9 and -1 9*-1=-9 and 9-1=8
