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3 years ago

Solve for y in terms of x: 3y-2x=7

Mathematics

2 answers:

Alenkasestr [34]3 years ago

7 0

Answer will be: y=7/3+2x/3

Dmitry_Shevchenko [17]3 years ago

3 0

Answer:

y = 2/3x + 7 / 3

Step-by-step explanation:

Step 1: Add 2x to both sides.

−2x+3y+2x=7+2x

3y=2x+7

Step 2: Divide both sides by 3.

3y / 3 = 2x+7 / 3

y= 2 / 3x + 7 / 3

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Please help. I need help with my math homework and I’m confused and I only have one attempt. Thanks in Advance!

Marrrta [24]

Answer:

x>-6, x<-4

Step-by-step explanation:

|x+5|>-1

x+5>−1 (Possibility 1)

x+5−5>−1−5 (Subtract 5 from both sides)

x>−6

x+5<−(−1)(Possibility 2)

x+5<1(Simplify both sides of the inequality)

x+5−5<1−5(Subtract 5 from both sides)

x<−4

x>-6 or x<-4

3 0

3 years ago

Express .32 as a fraction

nikdorinn [45]

Answer: 8/25

Step-by-step explanation: Using the place value chart, we can see that the decimal 0.32 is thirty-two hundredths so we can write 0.32 as 32/100.

Since 32/100 is not in lowest terms, we divide both the numerator and the denominator by 4 and we get the equivalent fraction 8/25.

This means that 0.32 can be written as the fraction 8/25 which is in lowest terms.

4 0

3 years ago

1.) Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth .x squared minus 21 x equals n

Andrew [12]

Part 1
We are given $x^2-21x=-4x$ . This can be rewritten as $x^2-18x=0$ .
Therefore, a=1, b=-18, c=0.
Using the quadratic formula
$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-\left(-18\right)\pm \sqrt{\left(-18\right)^2-4\left(1\right)\left(0\right)}}{2\left(1\right)}$
$x=\frac{18\pm 18}{2}$

The values of x are
$x_1=\frac{18-18}{2}=0$
$x_2=\frac{18+18}{2}=18$

Part 2
Since the values of y change drastically for every equal interval of x, the function cannot be linear. Therefore, the kind of function that best suits the given pairs is a quadratic function.

Part 3.
The first equation is $y=x^2+2$ .
The second equation is $y=3x+20$ .

We have
$x^2+2=3x+20$
$x^2-3x-18=0$
Factoring, we have
$\left(x-6\right)\left(x+3\right)=0$
Equating both factors to zero.
$x_1-6=0\rightarrow x_1=6$
$x_2+3=0\rightarrow x_2=-3$

When the value of x is 6, the value of y is
$y=3\left(6\right)+20=38$

When the value of x is -3, the value of y is
$y=3\left(-3\right)+20=11$

Therefore, the solutions are (6,38) or (-3,11)

7 0

3 years ago

Pls help me on this pls

Blizzard [7]

Answer:

1.B not sure about 2 though sorry i couldnt help u on 2 Step-by-step explanation:

5 0

3 years ago

Correct answer get the BRAINLIEST ANSWER!

OLga [1]

Here is how I completed the problem:

I started by creating a ratio:

$\frac{x}{0.18} + \frac{360}{0.10} = \frac{x+360}{0.15}$

<em>Where 'x' is the desired amount of the 18% solution of sulfuric acid.

</em>From here, I solved for 'x':
<em>
</em> $\frac{0.10x}{0.018} + \frac{360(0.18)}{0.018} = \frac{x+360}{0.15}$
$\frac{0.10x}{0.018} + \frac{64.8}{0.018} = \frac{x+360}{0.15}$
$\frac{0.10x+64.8}{0.018} = \frac{x+360}{0.15}$
$0.15(0.10x+64.8) = 0.018(x+360)$
$0.015x+9.72 = 0.018x+6.48$
$0.003x = 3.24$
$x = 1080$

∴You will need to add 1080ml of 18% Sulfuric Acid in order to obtain a 15% solution.

8 0

3 years ago