Is -1 less than -2

1 answer:

7 0

No, no, yes, yes, yes I believe. Hope this helps!!

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bekas [8.4K]

Answer:

Step-by-step explanation:

$\displaystyle \lim_{h \to 0} \frac{f(2+h)-f(2)}{h}$

$\displaystyle\lim_{h \to 0} \frac{(2+h)^2 + 2 + h + 1 - 2^2 - 2 - 1}{h}$

$\displaystyle\lim_{h \to 0} \frac{4 + 4h + h^2 + h - 4}{h}$

$\displaystyle\lim_{h \to 0} \frac{h^2 + 5h}{h}$

$\displaystyle\lim_{h \to 0} h + 5$

= 5

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Sedaia [141]

Just a moment while I review this

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Luba_88 [7]

Poor boy *Gives cookie*

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KonstantinChe [14]

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777dan777 [17]

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