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Ronch [10]
3 years ago
12

If f(x)=x-1/x g(x)=x-1 and h(x)=x+1 what is (g•h•f)(x)

Mathematics
2 answers:
eimsori [14]3 years ago
8 0

Answer:

( f o f )(x) = f ( f (x))

   = f (2x + 3)

   = 2(           ) + 3    ... setting up to insert the input

   = 2(2x + 3) + 3

   = 4x + 6 + 3

   = 4x + 9Step-by-step

explanation:

rosijanka [135]3 years ago
3 0

Answer:

x - 1/x, which is also f(x)

Step-by-step explanation:

hf(x) = x - 1/x + 1

hf(x) = x + 1 - 1/x

ghf(x) = x + 1 - 1/x - 1 = x - 1/x = f(x)

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GREYUIT [131]

Answer: 2=x

Step-by-step explanation:

4x-1 + 2x-1 = 5x

First combine like terms together

4x-1 + 2x-1 is 4x+2x-1-1

4x+2x-1-1 =6x-2

4x-1 + 2x-1=6x-2

6x-2=5x

The oppisite of 6x is -6x so -6x on both sides of equation to keep it balanced

6x-6x-2=5x-6x

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6 0
3 years ago
The difference between two numbers is 7. The sum of twice the larger number and three times the smaller number is 19.
Alex17521 [72]

Answer:

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Step-by-step explanation:

First, you identify your variables:

x= larger number

y= smaller number

Second, you find your equations:

x - y = 7

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Third, (I used the substitution method) you make "y" by itself for the 1st equation.

y = x - 7

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Then, you plug in the 1st equation for "y" in the 2nd equation

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Then, you distribute and simplify.

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6 0
2 years ago
Please answer this correctly without making mistakes
Mnenie [13.5K]

Answer:

<

Step-by-step explanation:

750,000,000 times 10^5 can be expressed as 7.5 times 10^{11}

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3 0
3 years ago
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Kobe has collected 750 football cards and 660 baseball cards. He wants to divide them into piles so that each pile has only one
Harrizon [31]

Answer: 30 cards

Step-by-step explanation:

To find the greatest possible number of cards in each pile such that there is the same number of cards in each​ pile we need to find the greatest common factor of 750 and 660.

Using Euclid division method , we have

750=1(660)+90\\\\660=7(90)+30\\\\90=3(30)+0

Hence, the greatest common factor of 750 and 660 = 30

Thus, there will be 30 cards in each pile.

4 0
3 years ago
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