part A
if the paperbacks are 40% less, that means 100% - 40% = 60%, they actually are 60% of the price of the hardcover ones.

part B
so, if they return it, they get 1/3 credit, if they try to sell it, is half off, which is more than 1/3. 22 got damaged.
![\bf \stackrel{\textit{damaged books at half-price}}{(22\cdot 14.994)\cfrac{1}{2}\implies 164.934}~\hfill \stackrel{\textit{damaged books at one-third price}}{(22\cdot 14.994)\cfrac{1}{3}\implies 109.956} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 164.934 - 109.956 = 54.978~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bdamaged%20books%20at%20half-price%7D%7D%7B%2822%5Ccdot%2014.994%29%5Ccfrac%7B1%7D%7B2%7D%5Cimplies%20164.934%7D~%5Chfill%20%5Cstackrel%7B%5Ctextit%7Bdamaged%20books%20at%20one-third%20price%7D%7D%7B%2822%5Ccdot%2014.994%29%5Ccfrac%7B1%7D%7B3%7D%5Cimplies%20109.956%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20164.934%20-%20109.956%20%3D%2054.978~%5Chfill)
part C
![\bf \textit{First Day}~\hfill \stackrel{hardcover}{3(24.99)}+\stackrel{paperback}{8(14.994)}+\stackrel{damaged}{3\left( 14.994\cdot \frac{1}{2} \right)} \implies 217.413 \\\\\\ \textit{Second Day}~\hfill \stackrel{hardcover}{4(24.99)}+\stackrel{paperback}{5(14.994)}+\stackrel{damaged}{8\left( 14.994\cdot \frac{1}{2} \right)}\implies 234.906 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill \boxed{17.493}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7BFirst%20Day%7D~%5Chfill%20%5Cstackrel%7Bhardcover%7D%7B3%2824.99%29%7D%2B%5Cstackrel%7Bpaperback%7D%7B8%2814.994%29%7D%2B%5Cstackrel%7Bdamaged%7D%7B3%5Cleft%28%2014.994%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%7D%20%5Cimplies%20217.413%20%5C%5C%5C%5C%5C%5C%20%5Ctextit%7BSecond%20Day%7D~%5Chfill%20%5Cstackrel%7Bhardcover%7D%7B4%2824.99%29%7D%2B%5Cstackrel%7Bpaperback%7D%7B5%2814.994%29%7D%2B%5Cstackrel%7Bdamaged%7D%7B8%5Cleft%28%2014.994%5Ccdot%20%5Cfrac%7B1%7D%7B2%7D%20%5Cright%29%7D%5Cimplies%20234.906%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%5Cboxed%7B17.493%7D)
I don't think she is incorrect, $17.5 is close to $20, she didn't say it was exactly $20, just thereabouts, and 17.5 is around that much.
=(-24÷6)×(-2)+7
=(-3×-2)+7
=6+7
=13
Very nice handwriting but the math and English are confusing.
Let's assume we're told

The subscript is important.
I think we're told the similar sum with 11 gives the smallest possible value for the sum. This is a rather cagey way of telling us 11 is the mean of the nine points. The mean is the number which minimizes the sum of squared deviations.


If 11 is the mean, the sum of the points is 9(11)=99.

Answer: 1080
Answer:
If every sixth student received a pencil and every ninth student received a notebook, 5 participants received both a pencil and a notebook.
Hope this helps!!
Answer:
c = 2, d = - 3
Step-by-step explanation:
Expand and simplify the left side then compare the coefficients of like terms on both sides.
5(2x + 1) + c(x + d) ← distribute parenthesis
10x + 5 + cx + cd
= x(10 + c) + 5 + cd
Compare like terms on both sides, that is
10 + c = 12 ( subtract 10 from both sides )
c = 2
Then
5 + cd = 5 + 2d and
5 + 2d = - 1 ( subtract 5 from both sides )
2d = - 6 ( divide both sides by 2 )
d = - 3