$58,685 would be the amount left over.
Answer:
-11
8 = 2x + 30
8 - 30 = -22
-22 ÷ 2 = -11
x = -11
Also if you place 2×(-11) + 30 you get 8
Answer:
6. B. x + 8
7. D. ( 3x-2)(3x-2)
8. D. Perfect square trimomal
9.C. x - 2
10. A. 3x and 8x
Step-by-step explanation:
Semoga Bermanfaat
The answer is 50º
Step-by-step explanation:
It is the correct and only plausable answer.
Answer:
a. 0.7291
b. 0.9968
c. 0.7259
Step-by-step explanation:
a. np and n(1-p) can be calculated as:

#Both np and np(1-p) are greater than 5, hence, normal approximation is most appropriate:

#Define Y:
Y~(11.04,5.7408)

Hence, the probability of 12 or fewer is 0.8291
b. The probability that 5 or more fish were caught.
#Using normal approximation:

Hence, the probability of catching 5+ is 0.9968
c. The probability of between 5 and 12 is calculated as;
-From b above
and a ,
=0.7291

Hence, the probability of between 5 and 12 is 0.7259