The rectangle shown has a perimeter of 64 cm and the given area (A=192 cm squared) it’s length is 8 more than twice it’s width.
The length of the rectangle is __ cm and the width of the rectangle is __ cm
1 answer:
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Answer:
<h2>Your Answer is C!!!!!!!!!</h2>Steps:
Add 2y to both sides:
Simplify:
Multiply both sides by 2:
2··6+2·2y
Simplify:
x>-12+4y
Answer:
length = 21 inches
Step-by-step explanation:
Missing information
In this question some information is missing the width is not given in the question .The width in this question is 4 inches we have to find the length of the rectangle .
We know that the perimeter of rectangle is given as
........................equation(1)
where p=perimeter
w= width
l= length
Now putting the value of width and perimeter in the equation(1) we get ,
50=8+2l
50-8=2l
42=2l
Therefore length of the dimension is 21 inches