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3 years ago

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The rectangle shown has a perimeter of 64 cm and the given area (A=192 cm squared) it’s length is 8 more than twice it’s width.

The length of the rectangle is __ cm and the width of the rectangle is __ cm

1 answer:

Mashcka [7]3 years ago

8 0

Hey there. please find an image attached.

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If GH = HI And FI =10 what is GI

ehidna [41]

Answer:

20

Step-by-step explanation:

By HL and CPCTC, GF = FI, so GI = 2FI = 2(10) = 20.

4 0

3 years ago

ABC Auto Insurance classifies drivers as good, medium, or poor risks. Drivers who apply to them for insurance fall into these th

Misha Larkins [42]

Answer:

a. $P(E_1/A)=0.0789$

b. $P(E_2/A)=0.395$ \

c. $P(E_3/A)=0.526$

Step-by-step explanation:

Let $E_1,E_2,E_3$ are the events that denotes the good drive, medium drive and poor risk driver.

$P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20$

Let A be the event that denotes an accident.

$P(A/E_1)=0.01$

$P(A/E_2=0.03$

$P(A/E_3)=0.10$

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem, $P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}$

We have to find $P(E_1/A)$

Using the Bayes theorem

$P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}$

Substitute the values then we get

$P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}$

$P(E_1/A)=0.0789$

b.We have to find the probability Mr.Brophy is a medium driver

$P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395$

c.We have to find the probability Mr.Brophy is a poor driver

$P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526$

7 0

3 years ago

Write the fractions as fractions with a common denominator 3/4 and 1/3

JulijaS [17]

3/4 and 1/3

4x3 = 12 that will be the common denominator.

For 3/4 we first divide 12/4 = 3 and then multiply 3 x3 = 9 that's the numerator

For 1/3 we first divide 12/3 = 4 and then multiply 1x4 = 4 that's the numerator

The fractions will be rewrited as: 9/12 and 4/12

3 0

1 year ago

4,284 passengers traveling by the intercity bus every day, the intercity bus operates 6 hours every day, find the number of pass

Lemur [1.5K]

Answer:

714

Step-by-step explanation:

So lets go over what we know.

The bus only goes for 6 hours each day.

So lets just think of a full day as 6 hours.

Each day(6 hours), 4284 passangers ride the bus.

To find passangers per hour, we must divide the total passangers by the total hours.

This is 4284(total passangers) divided by 6(total hours):

4284/6

=

714

So each hour, there are 714 passangers.

Hope this helps!

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3 years ago

Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES

olasank [31]

Answer:

1.d 2 a,d

Step-by-step explanation:

4 0

3 years ago