We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem.
Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.
Find the Volume
Volume
l = 27 cm
w = 14 cm
h = 22 cm
V = 27 *14 * 22
V = 8316 cm^3
Find the surface area
SA = 2*l*w + 2*l*h + 2*w*h
SA = 2*27*14 + 2*27*22 + 2*14*22
SA = 756 + 1188 + 616
SA = 2558
Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.
Another way to do this is to consider a cube which might give you a more useful result.
s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2


That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.
Answer:
Step-by-step explanation:
<u>Given GP with </u>
<u>Let the common difference is r, then</u>
<u>Solve for r and then a₁:</u>
- 4r = 7 ⇒ r = 7/4
- a₁(7/4)³ = 4
- a₁ = 4*(4/7)³ = 4⁴/7³ = 256/343
Answer:

Step-by-step explanation:
ΔABC and ΔADB are similar (AAA).
Therefore the corresponging sides are in proportion:

Substitute:

<em>cross multiply</em>

Answer:
The answer is (-4/3)
Step-by-step explanation:
3(x − 4) = 12x
Multiply (x – 4) by 3 we get,
3(x – 4) = 12x
3x – 12 = 12x
3x – 12x – 12 + 12 = 12x – 12x + 12
-9x = 12
-9x/(-9) = -12/9
x = -4/3
Thus, The value of x is -4/3
<u>-TheUnknownScientist 72</u>
The function shown in the graph is increasing over the interval (-1, 0) and (1, ∞). It is decreasing over the interval (-∞, -1) and (0, 1). The function does not remain constant.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
The function shown in the graph is increasing over the interval (-1, 0) and (1, ∞). It is decreasing over the interval (-∞, -1) and (0, 1). The function does not remain constant.
Find out more on equation at: brainly.com/question/2972832
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