Answer:
4 in. x 10in. x 3in. x 5in. x 2in. = 50in.
Step-by-step explanation:
Just as an example, three consecutive integers might be 4,5,6.
If x is the least of these (4 in our example), then the other two integers would be x+1, and x+2.
Then the sum of our three integers is x + (x+1) + (x+2).
Addition is commutative so we can switch any two terms, and it is also associative so we can regroup any terms. This lets is rearrange things with all the "x" together and all the numbers together like this:
(x+x+x) + (1+2) OR 3x + 3
According to the problem, the sum is 126, so 3x+3 = 126.
3x = 123
x = 41 (which is the smallest consecutive integer)
Check our answer: 41 + 42 + 43 = 126.
When you square +6 or -6 you get 36. That's less than 40.
When you square +7 or -7, you get 49. That's more than 40.
So one of the square roots of 40 is between <em>+6 and +7</em>, and
the other square root of 40 is between <em>-7 and -6 </em>.
X=5/8 or x=-4/3
here is the work if needed...
24x^2+17x-20=0
Step one: Factor left side of equation.
(8x-5)(3x-4)=0
Step two: Set factor equal to 0.
8x-5=0 or 3x-4=0
x=5/8 or x=-4/3
Answer:
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Step-by-step explanation: