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3 years ago

Please Help me on number 4

Mathematics

1 answer:

Iteru [2.4K]3 years ago

5 0

Step-by-step explanation:

a.here, 3x+y=6

reducing it into slope intercept form we get,

y=-3x+6

comparing it with y=mx+c we get,

slope(m)=-3 and

y-intercept (c)=6

b.here,y=5x+2

comparing it with y=mx+c we get,

slope(m)=5 and

y-intercept (c)=2

c.here,x=4y-1

reducing it into slope intercept form we get,

4y=x+1

or,y=x/4+1/4

comparing it with y=mx+c we get,

slope(m)=1/4 and

y-intercept (c)=1/4

d.here,y=-x+6

comparing it with y=mx+c we get,

slope(m)=-1 and

y-intercept (c)=6

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Two isosceles triangles are shown above. If b = 180-4a and a=35, What is the value of c?

Ymorist [56]

Answer:

a=35 given

b=40

c=110

I couldn't complete see c. Please look at the picture to see what I assumed it to be.

Step-by-step explanation:

Hmmm... I guess a and b are not vertical.

We are given b=180-4a and a=35 so b=180-4(35)=180-140=40.

So b=40.

Isosceles triangles always have congruent base angles. So let's call both of the base angles in the bottom triangle x.

That means x+x+40=180.

We need to solve this for x.

Combine like terms:

2x+40=180

Subtract 40 on both sides:

2x=140

Divide both sides by 2:

x=140/2

Simplify:

x=70

So I'm assuming that c and it's adjacent angle are sitting on a straightedge together which means 70+c=180.

70+c=180

Subtract 70 on both sides:

c=180-70

Simplify:

c=110

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