Question

Which ordered pair is a solution for the system of equations? {3x−5y=152x−y=−4 (−5, −6) (0, 3) (2, 8) (−6, −11)

Answer 1

3x-5y =15

2x-y=-4 
multiply the equation by 5 and then subtract   equation 2 from equation 1
so 3x-5y =15
    10x-5y =-20
-7x =35 x =-5  
plug in the value of x in the second equation -10 -y =-4  - y= -4 +10 y =-6
x=-5 y=-6

Answer 2

Answer:

(−5, −6)

Step-by-step explanation:

GIVEN : $3x-5y = 15$

             $2x-y = -4$

SOLUTION:

$3x-5y = 15$   ------EQUATION 1

$2x-y = -4$     ------ EQUATION 2

Now multiply the equation 2 by 5

⇒ $5(2x-y = -4)$  

⇒$10x-5y = -20$      ---(a)

Now , subtract (a) from equation i.e

$3x-5y-15-(10x-5y+20) = 0$

$3x-5y-15-10x+5y-20) = 0$

$-7x-35 = 0$

$-7x=35$

$x=\frac{35}{-7}$

$x=-5$

put x = - 5 in equation 1 to get value of y

$3(-5)-5y = 15$

$-15-5y = 15$

$-5y = 15+15$

$-5y = 30$

$y = \frac{30}{-5}$

$y = -6$

Thus (x,y) =(-5,-6) is a solution.