There are 36 dogs in the shelter.
<h3>How to find the total number of dogs in the shelter?</h3>
The ratio of dogs to cats in the shelter is given as 9:15.
The total number of dogs and cats is given as 96.
Let the constant of proportionality be x.
The total number of dogs is 9x and the total number of cats is 15x.
This means that:
9x + 15x = 96
24x = 96
x = 4.
The total number of dogs in the shelter = 9 × 4
= 36
Therefore, we have found that there are 36 dogs in the shelter.
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Answer:
It is not normally distributed as it has it main concentration in only one side.
Step-by-step explanation:
So, we are given that the class width is equal to 0.2. Thus we will have that the first class is 0.00 - 0.20, second class is 0.20 - 0.40 and so on(that is 0.2 difference).
So, let us begin the groupings into their different classes, shall we?
Data given:
0.31 0.31 0 0 0 0.19 0.19 0 0.150.15 0 0.01 0.01 0.19 0.19 0.53 0.53 0 0.
(1). 0.00 - 0.20: there are 15 values that falls into this category. That is 0 0 0 0.19 0.19 0 0.15 0.15 0 0.01 0.01 0.19 0.19 0 0.
(2). 0.20 - 0.40: there are 2 values that falls into this category. That is 0.31 0.31
(3). 0.4 - 0.6 : there are 2 values that falls into this category.
(4). 0.6 - 0.8: there 0 values that falls into this category. That is 0.53 0.53.
Class interval frequency.
0.00 - 0.20. 15.
0.20 - 0.40. 2.
0.4 - 0.6. 2.
If lines a and b are parallel, the two angles given would be the same.
2x - 5 = x + 20
x = 25
6 is one of the six total sides on a dice.
P(6)=1/6
1 is one of the six total sides on a dice.
P(1)=1/6
Im sure this means add because on a number line when you move to the right its adding. And since the amount of units were moving up by is 6 we would add 0+6 which equals 6.