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Ivanshal [37]
3 years ago
10

A rectangular planter can hold 2,304 cubic inches of soil. The dimensions of the base of the planter are 24 inches by 12 inches.

Mathematics
2 answers:
icang [17]3 years ago
5 0
2304/12/24=8
ANSWER=8
Makovka662 [10]3 years ago
3 0
Your answer should be 3) 16 inches.
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I suck at math so help me please:)
Evgen [1.6K]
Since they’re vertical we know that they’re congruent. We write the equation as 160=10x+50. Subtract 50 to both sides then we get 110=10x so now we divide 10 to both sides and get 11=x.
So your answer is A
Hope I helped :)
7 0
3 years ago
Aurora Corporation operated without insurance coverage for the first month of 2015. Then, on February 1, 2015, the company paid
vitfil [10]

Answer:

$2200

Step-by-step explanation:

$4800 premium for 2 years means for 2* 12 = 24 months, thus each month, the insurance expense is:

4800/24 = 200 dollars

Since they haven't used insurance in January, they will use insurance expense for the rest of the 12 - 1 = 11 months, thus the expense would be:

200 * 100 = $2200

4 0
3 years ago
Given that 6 x − 7 y = 22 Find y when x = − 1
kykrilka [37]

Answer

y= 4

Step-by-step explanation:

6x-7y=22

6x(-1)-7y=22

-6-7y=22

-7y=22+6

-7y=28

y=-4

7 0
2 years ago
You mow the lawn to earn your allowance. Each time you mow the lawn you earn \$12$12dollar sign, 12. Write an equation for the n
horrorfan [7]
For this case, the first thing we must do is define variables.
 m: number of times you cut the grass
 d: amount of dollars you earn.
 We now write the linear equation that models the problem:
 d = 12m
 The slope of the line is 12, which means that each time you cut the grass, you earn 12 dollars.
 Answer:
 
an equation for the number of dollars, d, you earn when you mow the lawn m times is:
 
d = 12m
6 0
3 years ago
Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
Mademuasel [1]

Answer:- a.The given expression is equivalent to  \frac{x^{10}y^{14}}{729}



Given expression:- [\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}

=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}

=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}

=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}

=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}

=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}

Thus a. is the right answer.


6 0
3 years ago
Read 2 more answers
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