The total distance was 35 miles. Why? Well, see below:
The student ran 3 miles each day for 5 days. That can be representative of:
Day 1: 3 miles
Day 2: 3 miles
Day 3: 3 miles
Day 4: 3 miles
Day 5: 3 miles
Adding these values together, we will find that the student ran a total of 15 miles in the first five days.
As for the next set of 5 days, we can represent this by modeling like we did above:
Day 6: 4 miles
Day 7: 4 miles
Day 8: 4 miles
Day 9: 4 miles
Day 10: 4 miles
Adding the values from the second set of days, we will find that in days 6-10, the student ran a total of 20 miles.
We can add the total values together to identify the total distance the student ran during these 10 days.
15 + 20 = 35 total miles
Hence, the student ran a total of 35 miles over the course of 10 days. If you need help, let me know and I will go ally assist you.
Answer:
A, B, and C
I think. Please let me know if wrong.
Heres what i did:
1.8 x 100 = 180.
180 - 80 = 100
(they made over 100 in profit)
A. 1.2 x 0 = 0
B. 1.2 x 40 - 48
C. 1.2 x 60 = 72
D. 1.2 x 70 = 84
E. 1.2 x 80 =96
D and E bot Exceed 80 so it has to be AB and C
Hope this Helps ☺
Answer:
The answer would be 9.4 units
Step-by-step explanation:
Answer:
4: 32a^5 5: 2a / bc^2
Step-by-step explanation:
4. (2a)^3 / (2a)^-2
= (2a)^3 * (2a)^2
= 8a^3 * 4a^2
= 32a^5
5. 10a^7 b^9 c^6 / 5a^6 b^10 c^8
= 2a^7 b^9 c^6 / a^6 b^10 c^8
= 2a / bc^2
