All categories

3 years ago

NEED BOTH ANSWERED!!!Is the relation a function?○ True○ False

Mathematics

1 answer:

LiRa [457]3 years ago

8 0

Answer:

The first picture without the diagram is true, and the other one is false.

Step-by-step explanation:

A relation can be a function if the domain has exactly one range. IT CANT HAVE TWO Y-VALUES.

You might be interested in

What is the unit cost per bottle if a pack of 4 bottles of juice sells for $3?

iragen [17]

A is the answer for your question

5 0

3 years ago

Read 2 more answers

1 pt The largest exponent of a polynomial determines the _________. Cubic Linear Exponent Degree

Y_Kistochka [10]

Answer: 3

Step-by-step explanation:

5 0

3 years ago

A credit card company charges 22% interest fee on any charges not paid at the end of the month.. If the bill totals $450 for thi

kifflom [539]

I think the answer is 450x .22= 99$

6 0

3 years ago

50 people are selected randomly from a certain population and it is found that 12 people in the sample are over 6 feet tall. wha

Taya2010 [7]

Answer:

The point estimate of the proportion of people over 6ft to total people is 6:25

Step-by-step explanation:

To find this, simply start with the number of people over 6 ft and total people as a proportion.

12:50

Then simplify by dividing by 2

6:25

8 0

3 years ago

Use the following table for questions 11-13.A baseball manager believes a linear relationship exists between the number of Home

slamgirl [31]

The regression equation of Y on X is given by the following formula:

$Y-\bar{Y}=b_{yx}(X-\bar{X})$

Where byx is given by the formula:

$b_{yx}=\frac{N\sum^{}_{}XY-\sum^{}_{}X\sum^{}_{}Y}{N\sum^{}_{}X^2-(\sum^{}_{}X)^2}$

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.

The table of values is:

The values we need to know are on the following table:

By replacing the known values in the formula we obtain:

$\begin{gathered} b_{yx}=\frac{8\cdot26125-167\cdot995}{8\cdot4649-(167)^2} \\ b_{yx}=\frac{209000-166165}{37192-27889} \\ b_{yx}=\frac{42835}{9303} \\ b_{yx}=4.6 \end{gathered}$

Now, the average of X and Y is the sum divided by N, then:

$\begin{gathered} \bar{X}=\frac{167}{8}=20.87 \\ \bar{Y}=\frac{995}{8}=124.37 \end{gathered}$

Replace these values in the formula and find the regression equation as follows:

$\begin{gathered} Y-124.37=4.6(X-20.87) \\ Y-124.37=4.6X-4.6\cdot20.87 \\ Y=4.6X-96.11+124.37 \\ Y=4.6X+28.26 \end{gathered}$

The answer is a) y=4.6x+28.26

7 0

2 years ago