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ra1l [238]
3 years ago
13

Two cargo trains are linked together, making of a total of 22 cars. The cars from one of the trains are carrying 15 tons each, a

nd those from the other train are carrying 20 tons each. If the total cargo weight ranges from 380 to 400 tons, what is the range of the number of 20 tons cars? (Fill in the equation)
Let x be the number of 20 tons cars.

380 < 15 ( ) + 20 < 400
Mathematics
1 answer:
DochEvi [55]3 years ago
6 0
Let x be the number of 20 ton cars

Then,
380<{15(22-x)+20x}<400
380<{330-15x+20x}<400
380<{330+5x}<400

Subtract 330 on both sides
50<5x<70

Divide both sides by 5;
10<x<14

Therefore, the range of 20 tonne cars is between 10 and 14 cars.
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Ryan got $25 for his birthday. His dad told him not to spend it all in one place, so he wants to divide it up evenly between 5 c
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Need HELP PLS PIC ATTACHED
Vera_Pavlovna [14]

Answer:

4x^{2}-13x+10

Step-by-step explanation:

(4x+5)(x-2)

Multiply each term in the first parenthesis by each term in the second (foil)

Step 1: Expand it by writing out each multiplication. I added a picture showing which order to do it. (go in order of green, red, blue, yellow.) (you can remember this as first, outside, inside, last.)

When you expand it'll look like: 4x⋅x+4x⋅-2-5x-5⋅-2

Step 2: Calculate product

4x⋅x+4x⋅-2-5x-5⋅-2 (for the 4x⋅x it would be written like 4x^{2})

   4x^{2}+4x⋅-2-5x-5⋅-2

4x^{2}+4x⋅-2-5x-5⋅-2 (4x⋅-2 becomes -8x) (multiply 4x times -2)

4x^{2}-8x-5x-5⋅-2

4x^{2}-8x-5x-5⋅-2 (-5⋅-2 becomes +10) (multiply -5 times -2)

4x^{2}-8x-5x+10

Step 3: collect like terms

4x^{2}-8x-5x+10 (-8x-5x becomes -13x) (-8x times -5x)

4x^{2}-13x+10 is the most simplified so it should be your final answer

4 0
1 year ago
A metalworker has a metal alloy that is 25% copper and another alloy that is 60% copper.How many kilograms of each alloy should
Neporo4naja [7]

Answer:

20kg of 25% copper alloy

30kg of 60% copper alloy

Step-by-step explanation:

There are 2 kinds of metal, first metal(A) have 25% copper while the second metal(B) has 60% copper. The metalworker want to create 50kg of metal, which means the total weight of both metals is 50kg (A+B = 50). The metalworker also want the metal made of a 46% which is 23kg(0.25A + 0.6B = 0.46*50). From these sentences, we can derive 2 equations. We can solve this with substitution.

A+B = 50

A= 50-B

Let's put the first equation into the second.

0.25A + 0.6B = 0.46 *50

0.25(50-B) + 0.6B =23

12.5 - 0.25B + 0.6B =23

0.35B=23 -12.5

B= 10.5/ 0.35= 30

Then we can solve A

A= 50-B

A= 50-30

A=20

8 0
3 years ago
I need help with my algerbra
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I can help you what problem??
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