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qwelly [4]
3 years ago
7

Explain the distance formula. Then use it to calculate the

Mathematics
2 answers:
34kurt3 years ago
8 0

Answer:  The required distance between the points between A(1, 1) and B(7, −7) is 10 units.

Step-by-step explanation:  We are given to explain the distance formula. Also, to calculate the distance between A(1, 1) and B(7, −7).

<em><u>Distance formula :</u></em>  The distance between any two two points with co-ordinates (a, b) and (c, d) is given by

D=\sqrt{(c-a)^2+(d-b)^2}.

Therefore, the distance between the points A(1, 1) and B(7, −7) is given by

D\\\\=\sqrt{(7-1)^2+(-7-1)^2}\\\\=\sqrt{36+64}\\\\=\sqrt{100}\\\\=10.

Thus, the required distance between the points between A(1, 1) and B(7, −7) is 10 units.

Alex777 [14]3 years ago
6 0

Answer:

dAB=10\ units

Step-by-step explanation:

we know that

The <u>distance formula</u> is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points

The formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(1, 1) and B(7, −7)

Let

(x1,y1)=A(1, 1)

(x2,y2)=B(7, −7)

substitute the given values in the formula

dAB=\sqrt{(-7-1)^{2}+(7-1)^{2}}

dAB=\sqrt{(-8)^{2}+(6)^{2}}

dAB=\sqrt{64+36}

dAB=\sqrt{100}

dAB=10\ units

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3 years ago
The sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.
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Answer:

2 \frac{1}{16}

Step-by-step explanation:

The question state that;  the sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.

First, we need to interpret and represent this statement mathematically

Let n be the number.

The sum means 'addition'

1/6 of that number is  1/6 of n = 1/6 × n  = \frac{n}{6}

2 1/2 of that number is 2 1/2 of n = 2 1/2 × n  = 5/2 × n = \frac{5n}{2}

So the question says that, when we add; \frac{n}{6} ,  \frac{5n}{2}  and 7 all together, the value is 12 1/2

That is;

\frac{n}{6}  + \frac{5n}{2} + 7 = 12 1/2

\frac{n}{6}  + \frac{5n}{2} + 7  = \frac{25}{2}         ( changing 12 1/2 to improper fraction will give  \frac{25}{2} )

So we can now go ahead and solve for n

\frac{n}{6}  + \frac{5n}{2} + 7  = \frac{25}{2}  

subtract 7 from both-side of the equation

\frac{n}{6}  + \frac{5n}{2}   =  \frac{25}{2}   -   7

\frac{n + 15n}{6}  =   \frac{25 -14}{2}

\frac{16n}{6}      =    \frac{11}{2}

\frac{16n}{6}  can be reduced to give us \frac{8n}{3}

\frac{8n}{3}   =   \frac{11}{2}

Cross multiply

8n × 2  = 11× 3

16n = 33

Divide both-side of the equation by 16

\frac{16n}{16}    =   \frac{33}{16}

(On the left-hand side of the equation, 16 will cancel-out 16 leaving us with just, while  on the right-hand side of the equation 33 will be divided by 16)

n =  \frac{33}{16}     = 2\frac{1}{16}

Therefore the number is  2\frac{1}{16}

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