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2 years ago

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In AJKL, the measure of ZL=90°, JL = 55, LK = 48, and KJ = 73. What

1 answer:

Juli2301 [7.4K]2 years ago

3 0

Together I think it’s the same way that you can get the one to the one you have on your computer problems you have no proof that I have it on my computer problems I have lost all the same information I I don’t have any proof that you are in my account so so much you have to pay for it and I’m sorry you don’t know where I can get you I know I

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Find the values of a such that the solution

e-lub [12.9K]

Answer:

The solution is the interval (-∞,5]

Step-by-step explanation:

we have

$x\leq 5$

The solution is the interval -----> (-∞,5]

All real numbers less than or equal to 5

In a number line the solution is the shaded area at left of x=5 (close circle)

see the attached figure

8 0

2 years ago

in a final exam you have four multliple choice questions left to do. each questions has five suggested answers and only one of t

kompoz [17]

Answer:

The probability that you get zero questions correct is 0.4096

The probability that you get one questions correct is 0.4096

The probability that you get three questions correct is 0.0256

Step-by-step explanation:

These probability can be describe with a Binomial Distribution. These distribution can be used when we have n identical and independent situations in which there is a probability p or probability of success and a probability q or probability of fail. Additionally q is equal to 1 - p. The probability of x for a situation in which we can apply binomial distribution is:

$P( x,n,p) = n Cx * p^{x } * q^ {n-x}$

Where x is the variable that says the number of success in the n situations

And nCx is calculate as:

$nC x = \frac{ n!}{ x! (n-x)! }$

From the question we can identify that:

n is equal to 4 multiple choice question
p is 1/5 or 0.2, the probability of get one question correct
q is 4/5 or 0.8, the probability of get one question incorrect

Then the probability of get zero questions correct of 4 questions is:

$P( 0, 4, 0.2) = 4 C0 * p^{0 } * q^ {4-0}= 0.4096$

The probability of get one question correct of 4 questions is:

$P( 1, 4, 0.2) = 4 C1 * p^{1 } * q^ {4-1}= 0.4096$

The probability of get three questions correct of 4 questions is:

$P( 3, 4, 0.2) = 4 C3 * p^{3 } * q^ {4-3}= 0.0256$

8 0

3 years ago

How would you solve this problem 999 + 587 = 1000 + what = what ? How would this problem be solved

bija089 [108]

Answer:

2,586

Step-by-step explanation:

Add 1000+1000

2000

Since its 999 not 1000 subtract 1

1999

Now add 1 and subtract 1 from 587

Then add 2000 with 586

2,586

3 0

2 years ago

Read 2 more answers

Kanye and jay wanted to see who could run faster in a minute.They both started in the same spot and ran in different directions.

Lena [83]

Answer:

Kanye run faster.

Step-by-step explanation:

Given that,

Time = 1 min = 60 sec

Suppose, we find the speed of kanye and Jay.

According to number line,

Kanye covers the -160m distance and Jay covers the 140 m distance.

Negative sign shows the opposite direction.

We need to calculate the speed of Kanye

Using formula of speed

$v=\dfrac{d}{t}$

Where, v = speed

d = distance

t = time

Put the value into the formula

$v=\dfrac{160}{60}$

$v=2.66\ m/s$

We need to calculate the speed of Kanye

Using formula of speed

$v=\dfrac{d}{t}$

Put the value into the formula

$v=\dfrac{140}{60}$

$v=2.33\ m/s$

The speed of kanye is more than jay.

Hence, Kanye run faster.

6 0

2 years ago

What is 7/10 - 1/10 in its simplest form

Elenna [48]

3/5 cause you get the lowest common denominator

4 0

2 years ago

Read 2 more answers