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katrin [286]
3 years ago
9

______ is a group of diseases characterized by uncontrolled growth and spread of abnormal cells in the body and can be caused by

both internal and external factirs
Mathematics
2 answers:
Artyom0805 [142]3 years ago
5 0

Answer:

cancer

Step-by-step explanation:

Apex approved

grandymaker [24]3 years ago
3 0
Cancer if its not controlled it's can cause death
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Which set of numbers has 21 as a common factor?
Soloha48 [4]

Answer:

the answer is A {126,168,189}

7 0
2 years ago
If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
Sal bought 2 shirts and a hat. Sal remembers each shirt was $10, and the total was $50. Which equation helps answer the question
Oksana_A [137]

Answer: the hat= $30. The equation you would use to solve is 2s+h=50

Step-by-step explanation:

2s+h=50

2(10)+h=50

20+h=50

-20. -20

h=30

3 0
3 years ago
Four less than a number is twenty
Solnce55 [7]
The answer would be 24 because 24-4 is 20
7 0
3 years ago
Read 2 more answers
Which lines are perpendicular to the line y – 1 = (x+2)? Check all that apply.
Ilya [14]

Answer:

none of them

Step-by-step explanation:

Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.

line 1:  

y – 1 = (x+2)

y = x + 3

slope of line 1 = 1

line 2:  

y + 2 = –3(x – 4)

y + 2 = -3*x + 12

y =  -3*x + 10

slope of line 2 = -3

m1*m2 = 1*(-3 ) = -3

They are not perpendicular

line 3:  

y − 5 = 3(x + 11)

y − 5 = 3*x + 33

y = 3*x + 38

slope of line 3 = 3

m1*m3 = 1*3 = 3

They are not perpendicular

line 4:  

y = -3x –  

slope of line 4 = -3

m1*m4 = 1*(-3 ) = -3

They are not perpendicular

line 5:  

y = x – 2

slope of line 5 = 1

m1*m5 = 1*1 = 1

They are not perpendicular

line 6:  

3x + y = 7

y = -3x + 7

slope of line 6 = -3

m1*m6 = 1*(-3 ) = -3

They are not perpendicular

5 0
3 years ago
Read 2 more answers
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