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vaieri [72.5K]
3 years ago
10

In a class of 18 children, 13 have pet dogs at home, 11 have pet cats, and 8 have both. How many kids do not have four-legged pe

ts at home?
Mathematics
2 answers:
8_murik_8 [283]3 years ago
8 0

Answer:

2 people

Step-by-step explanation:

8 have both that means that of the 11 people that have cats 3 have only cats and of the 13 that have dogs 5 only have dogs therefore 2 people don't have four-legged animals at home

kirza4 [7]3 years ago
8 0

Answer:

2

Step-by-step explanation:

it starts out with 18 students, 24 pets in total. -16 for the dogs and cats, to lead up to 8, and 10 students left after subtracting 8 for how many students don't have a pet at home. So 2 students shouldn't have four legged pets left after subtracting the rest.  (this is my answer, it's probably wrong, i think you should wait for more,)

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<em>The right question is:</em>

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Answer:

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<em></em>

Step-by-step explanation:

Given

\frac{1}{2}x - 3y = 9

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Required

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Make y the subject of formula in the second equation

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Substitute y = 28 - 5x in the first equation

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Open the bracket

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Collect Like Terms

\frac{1}{2}x  + 15x = 9+ 84

\frac{x}{2}  + 15x = 9+ 84

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x = 6

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y = 28 - 5 * 6

y = 28 - 30

y = -2

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