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Effectus [21]
4 years ago
12

Which of the following expressions represents "the sum of n and the sum of 8 and 6"?

Mathematics
2 answers:
inessss [21]4 years ago
7 0
The sum of 8 and 6 is 8 + 6
The sum of n and the sum of 8 and 6 is n + (8 + 6)

So the answer is B
Goshia [24]4 years ago
4 0

Answer:

From the given expressions,  n+ ( 8 + 6 ) is the correct expression to express the phrase "the sum of n and the sum of 8 and 6"

Step-by-step explanation:

We can express a phrases into mathematical expression by using basic operations.

We are given a phrase "the sum of n and the sum of 8 and 6".

We write it mathematically using operations.

the phrase "Sum of 8 and 6" is represented mathematically as 8 + 6

again , the phrases " sum of n and ( 8 + 6 ) can be represented as n+ ( 8 + 6 )

Thus, from the given expressions,  n+ ( 8 + 6 ) is the correct expression to express the phrase "the sum of n and the sum of 8 and 6"

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3 years ago
The graph of f(x)=cos(x) is transformed to a new function, g(x) , by stretching it horizontally by a factor of 4 and shifting it
SpyIntel [72]

The equation of the new function is g(x)= cos4 x+1

Explanation:

The Parent function is f(x)=cos x

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8 0
3 years ago
Construct the confidence interval for the population mean mu. c = 0.90​, x = 16.9​, s = 9.0​, and n = 45. A 90​% confidence inte
Georgia [21]

Answer:

The  90%  confidence interval for population mean is   14.7  <  \mu  <  19.1

Step-by-step explanation:

From the question we are told that

   The sample mean is  \= x  =  16.9

    The confidence level is  C  =  0.90

     The sample size is  n  =  45

     The standard deviation

Now given that the confidence level is  0.90 the  level of significance is mathematically evaluated as

       \alpha =  1-0.90

       \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2}  from the standardized normal distribution table. The values is  Z_{\frac{\alpha }{2} } =  1.645

The  reason we are obtaining critical values for \frac{\alpha }{2}  instead of  that of  \alpha  is because \alpha  represents the area under the normal curve where the confidence level 1 - \alpha (90%)  did not cover which include both the left and right tail while \frac{\alpha }{2}  is just considering the area of one tail which is what we required calculate the margin of error

  Generally the margin of error is mathematically evaluated as

        MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

         MOE  = 1.645*  \frac{ 9 }{\sqrt{45} }

         MOE  = 2.207

The  90%  confidence level interval is mathematically represented as

      \= x  -  MOE  <  \mu  <  \= x  +  MOE

substituting values

     16.9 -  2.207  <  \mu  <  16.9 +  2.207

    16.9 -  2.207  <  \mu  <  16.9 +  2.207

     14.7  <  \mu  <  19.1

         

3 0
4 years ago
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