Jose constructed Triangle DCE, where m

Mathematics

2 answers:

lord [1]2 years ago

8 0

Answer:

is there a picture or can you at least finish the sentence

Step-by-step explanation:

Tju [1.3M]2 years ago

7 0

You have to connect the point D with the half lenth of the line CE and then you have to connect the point C with the line ED. Where the two lines cross, there is the middle.

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Answer:

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Step-by-step explanation:

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Fudgin [204]

Answer and workings in the attachment below.

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3 years ago

-25 Points-

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$\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}$