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3 years ago

Jose constructed Triangle DCE, where m

Mathematics

2 answers:

lord [1]3 years ago

8 0

Answer:

is there a picture or can you at least finish the sentence

Step-by-step explanation:

Tju [1.3M]3 years ago

7 0

You have to connect the point D with the half lenth of the line CE and then you have to connect the point C with the line ED. Where the two lines cross, there is the middle.

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Please help! I will mark as brainliest IF answer is right. <3

trasher [3.6K]

Solution

write the division as a fraction = 12y^4-4y^3 - 6y^2 + 36y - 22 over y-3 multiplied by r over y-3

r ×(2y^4 - 4y^3- 16y^2 + 36y- 22) over (y-3)^2

2ry^4 - 4ry^3 - 16ry^2 + 36ry - 22r over (y-3)^2

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20" id="TexFormula1" title=" \frac{1}{3} " alt=" \frac{1}{3} " align=

VikaD [51]

I hope this helps you 2 (B+4)=3 B+4=3/2 B=3/2-4 B=-5/2

5 0

3 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

3 years ago

Please help me with this one

Vladimir79 [104]

Is 10 and 15 because they both have a value of .909

8 0

2 years ago

4x + 1 = 2x - 5<br> show all steps

konstantin123 [22]

How to solve your question

Your question is

−

4x+1=2x-5

4x+1=2x−5

Solve

Subtract

from both sides of the equation

Simplify

Subtract

from both sides of the equation

Simplify

Divide both sides of the equation by the same term

Simplify

Solution

−

3 0

3 years ago

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