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loris [4]
3 years ago
15

Arman sets the goal for his sales team to increase revenue by 40%. Which main function of a manager does this demonstrate?

Business
1 answer:
Tcecarenko [31]3 years ago
8 0
The main function that demonstrated by Arman is : Planning

In this step, Arman hasn't yet started how to achieve that goal. But he's already decided the benchmark for his team and started to formed various strategies that they can do

hope this helps
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Explanation:

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The best mechanisms known today for efficiently providing goods and services are:
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Acme-Jones Corporation uses a weighted-average perpetual inventory system. August 2, 24 units were purchased at $23 per unit. Au
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Answer:

Cost of goods sold= $816

Explanation:

Giving the following information:

Acme-Jones Corporation uses a weighted-average perpetual inventory system.

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August 18: 40 units were purchased at $25 per unit.

On August 29: 34 units were sold.

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5 0
3 years ago
A company estimates that the revenue (in dollars) from the sale of x doghouses is given by R(x)=14,000ln(0.01x+1). Use the diffe
melamori03 [73]

Answer: The change in revenue for the sale of 1 more doghouse $ 66.67 dollars

Explanation: Differential is a function that can be used to approximate function value with a great degree of accuracy. This is done by the following.

Mathematical definition of derivative: f'(x) = lim f(x+Δx) - f(x)/Δx.

If Δx is very small:

f'(x) . Δx ≅ f(x+Δx) - f(x)

Knowing that Δy ≅ f(x+Δx) - f(x) and the diferential of variable x can be written by dx as the variable y can be dy:

dy = f'(x) dx

which means that the differential dy is approximately equal to the change Δy, if Δx is very small.

For the question, R(x) = y(x) = 14,000ln(0.01x+1)

f'(x) = \frac{d[14,000.ln(0.01x+1)]}{dx}

Using the chain rule, the derivative will be:

f'(x) = 14,000.\frac{0.01}{0.01x+1}

dy = 14,000.\frac{0.01}{0.01x+1}.dx

dx is the change in x. For the question, the change is 1 (1 more doghouse) and x is 110:

dy = 14,000\frac{0.01}{0.01.110+1}.1

dy = \frac{140}{2.1}

dy = 66.67

The change in revenue is $66.67 dollars.

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