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AveGali [126]
3 years ago
12

How many elements are in the set {whole numbers between 3 and 15}? 11 12 13

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
7 0
Let S be the set of whole numbers between 3 and 15 then <span>S={3,4,5,6,7,8,9,10,11,12,13,14,15}</span> so How many elements are in the set ? just count them..
Softa [21]3 years ago
7 0

Whole numbers between 3 and 15 are given by:

{4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14}

Therefore, to answer the question, what we must do is to count the number of whole numbers that we have inside the set.

We note that, without including number 3 and including number 15, the number of integers is equal to 11.

Answer:

There are 11 elements in the set of whole numbers between 3 and 15.

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xxTIMURxx [149]

Answer:

-4 ..... 1.5

-5......0

-2......2.5

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7 0
3 years ago
The value of 4c + 5g if c = 2 and g = 1.5
bixtya [17]

Answer:

15.5

Step-by-step explanation:

4c + 5g

= 4(2) + 5(1.5)

= 8 + 7.5

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4 0
3 years ago
Explain how to find the vertex of 2x^2+12x+16
Elina [12.6K]

The vertex form:

y=a(x-h)^2+k\\\\(h,\ k)-vertex

Use (a+b)^2=a^2+2ab+b^2\qquad(*)


2x^2+12x+16=2(x^2+6x)+16=2(x^2+2(x)(3))+16\\\\=2(\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2)+16=2((x+3)^2-9)+16\\\\=2(x+3)^2+(2)(-9)+16=2(x+3)^2-18+16\\\\=\boxed{2(x-(-3))^2-2}\to h=-3,\ k=-2

<h3>Answer: (-3, -2).</h3>

Other method:

f(x)=ax^2+bx+c\\\\vertex:(h,\ k)\\\\h=\dfrac{-b}{2a},\ k=f(h)

We have

f(x)=2x^2+12x+16\\\\a=2,\ b=12,\ c=16

Substitute:

h=\dfrac{-12}{(2)(2)}=\dfrac{-12}{4}=-3\\\\k=f(-3)=2(-3)^2+12(-3)+16=2(9)-36+16=18-36+16=-2

<h3>Answer: (-3, -2).</h3>
5 0
4 years ago
Tyler and Erin go out to eat . their food and beverages cost 52.25 and there is an 8% meals tax, how much is the bill? write you
drek231 [11]

Answer:

56.43

Step-by-step explanation:

52.25 + 4.18 (8% tax)

7 0
2 years ago
10 POINTS
yawa3891 [41]
About three years. Hope it helps!
4 0
3 years ago
Read 2 more answers
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