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saveliy_v [14]
3 years ago
7

brine's kitchen has an area of 81 square feet. the kitchen is 9 times as many square feet as brine's pantry. if the pantry is 3

feet wide, what is the length of the pantry?
Mathematics
1 answer:
maks197457 [2]3 years ago
8 0
So 81/9=9 so area of pantry is 9

3 times x=9
3x=9
divide both sides by 3
x=3

legnth/width=3
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the concrete slab under a garage measures 38 feet by 37 feet and is 6 inches thick. if concrete costs 150$ for a cubic yard, how
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STEP 1
find cubic feet; multiply the three dimensions together; be sure to use the same unit of measure for all three dimensions: 6 inches is equal to 1/2'.

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divide cubic feet in step 1 by number of cubic feet in a cubic yard

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3 0
3 years ago
Read 2 more answers
Find the arc-length parametrization of the curve that is the intersection of the elliptic cylinder x 2 + y 2/2 = 1 and the plane
storchak [24]

Answer:

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

0 ≤ Ф ≤ 4π.

Step-by-step explanation:

since x²+y²/2 = 1, then x²+s² = 1, with s = (y/√2)². Hence, (x,s) = (cos(Ф),sin(Ф)) and (x,y,z) = (cos(Ф),√2 sin(Ф), cos(Ф)-2). This expression evaluated in zero gives as result (1,0,-1). The derivate of this function is (-sin(Ф),√2 cos(Ф), -sen(Ф))

the norm of the derivate is √(sin²(Ф) + 2cos²(Ф)+sin²(Ф)) = √2. In order to make the norm equal to 1, i will divide Ф by √2, so that a √2 is dividing each term after derivating.

We take

f(\theta) = (cos(\frac{\theta}{\sqrt2}), \sqrt2 sin(\frac{\theta}{\sqrt2}), cos(\frac{\theta}{\sqrt2})-2)

Note that

  • f(0) = (1,0,-1)
  • f'(\theta) = (\frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2}, cos(\frac{\theta}{\sqrt2})}, \frac{sin(\frac{\theta}{\sqrt2})}{\sqrt2})

Whose square norm is 1/2cos²(Ф/2)+sen²(Ф/2)+1/2cos²(Ф/2) = 1. This is te parametrization that we wanted.

The values from Ф range between 0 an 4π, because the argument of the sin and cos is Ф/2, not Ф, Ф/2 should range between 0 and 2π.

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