Find the measure of each exterior angle of a regular polygon with 24 sides

2 answers:

8 0

The formula for finding the measure of each exterior angle of a regular polygon is similar to the formula for finding the measure of each interior angle. We take the sum of the measures of the exterior angles which is always 360 degrees and we divide this by the number of sides in the polygon which is n. So the formula for finding the measure of each exterior angle of a regular polygon is simply 360 over n. In this problem since the polygon has 24 sides, we simply plug a 24 in for n and we have 360 over 15. 360 divided by 24 is 15. Therefore, the measure of each exterior angle of a regular polygon that has 24 sides is 15 degrees.

lorasvet [3.4K]3 years ago

6 0

The measure of each interior angle would be 165 degrees

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4 years ago

Three of these expressions are equal to the volume of the barn shown. Which expression is not?

timurjin [86]

The statement that does not match the others is the one at lower right.

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The barn's volume can be decomposed into a rectangular prism and a triangular one. Thus the upper right expression is a true represenation of the barn's volume:

... Volume of triangular prism + Volume of rectangular prism

The volume of a rectangular prism is the product of its dimensions. The dimensions of the rectangular prism portion of the barn's volume are a, b, c, so the volume of that portion is ...

... Volume of rectangular prism = a·b·c

The volume of a triangular prism is the area of the triangular base multiplied by the length of the prism. Here, the triangular base has base dimension b and height (d-c), so its area is ...

... Area of triangular barn end = (1/2)b(d-c)

Since the length of the barn is "a", the volume of the triangular prism is ...

... Volume of triangular prism = (1/2)b(d-c)a = (1/2)·a·b·(d-c)

The total volume is the sum of the volumes of the parts ...

... a·b·c + (1/2)·a·b·(d-c) . . . . . . matches the upper right selection

This can be factored by removing a·b to outside parentheses:

... a·b·((1/2)·(d-c) + c) . . . . . . . . . matches the lower left selection

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Since the two left selections match the one at upper right, the odd one is the one at lower left.