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Artemon [7]
3 years ago
11

Three of these expressions are equal to the volume of the barn shown. Which expression is not?

Mathematics
2 answers:
timurjin [86]3 years ago
7 0

The statement that does not match the others is the one at lower right.

_____

The barn's volume can be decomposed into a rectangular prism and a triangular one. Thus the <em>upper right</em> expression is a true represenation of the barn's volume:

... Volume of triangular prism + Volume of rectangular prism

The volume of a <em>rectangular prism</em> is the product of its dimensions. The dimensions of the rectangular prism portion of the barn's volume are a, b, c, so the volume of that portion is ...

... Volume of rectangular prism = a·b·c

The volume of a <em>triangular prism</em> is the area of the triangular base multiplied by the length of the prism. Here, the triangular base has base dimension b and height (d-c), so its area is ...

... Area of triangular barn end = (1/2)b(d-c)

Since the length of the barn is "a", the volume of the triangular prism is ...

... Volume of triangular prism = (1/2)b(d-c)a = (1/2)·a·b·(d-c)

The <em>total volume</em> is the sum of the volumes of the parts ...

... a·b·c + (1/2)·a·b·(d-c) . . . . . . matches the <em>upper right</em> selection

This can be factored by removing a·b to outside parentheses:

... a·b·((1/2)·(d-c) + c) . . . . . . . . . matches the <em>lower left</em> selection

___

Since the two left selections match the one at upper right, the odd one is the one at lower left.

True [87]3 years ago
5 0

Answer:

bottom right for ttm

Step-by-step explanation:

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1 year ago
Please Help? A circle has an arc length of 5π in. The central angle for this arc measures π/3 radians. What is the area of the a
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Answer:

The area of the associated sector is \frac{25}{24}\pi \ in^{2}  

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The circumference of a circle is equal to

C=2\pi r

we have

C=5\pi\ in

substitute and solve for r

5\pi=2\pi r

r=2.5\ in

step 2

Find the area of the circle

we know that

The area of the circle is equal to

A=\pi r^{2}

we have

r=2.5\ in

substitute

A=\pi (2.5^{2})=6.25\pi\ in^{2}

step 3

Find the area of the associated sector

we know that

2\pi\ radians subtends the complete circle of area 6.25\pi\ in^{2}

so

by proportion

Find the area of a sector with a central angle of \pi/3\ radians

\frac{6.25\pi }{2\pi} =\frac{x}{\pi/3}\\x=6.25*(\pi/3)/2\\ \\x=\frac{25}{24}\pi \ in^{2}

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