Answer:
You can use the Law of Sines for this problem, but what makes it tough at first glance is that they put a step in before you can use it directly. That first step is to get m∠C. When solving a triangle, always get the third angle if you know the other two so that you can use the Law of Sines (or Law of Cosines) more directly.
The sum of the angles of any triangles is 180°. We know the measures of the two other angles. So we subtract them from 180° to find that third angle.
180° - 76° - 66° = 38°
Now we can use the proportion from the picture. Angle B measures 76°, side b is our unknown, Angle C measures 38°, and side c measures 3 units.
sin 76° sin 38°
----------- = -----------
b 3
Cross multiply to find b (the side). We carry out five places in these calculations to get more accuracy.
3 * sin 76° = b * sin 38°
b = 3 * sin 76° 3 * 0.56611 1.69832
--------------- = --------------- = ---------------- = 5.73044
sin 38° 0.29636 0.29636
To the nearest tenth, b - 5.7 units.
Step-by-step explanation:
google hope this helps
Rays CA and CB form the angle ACB
16. would be C since they both consist of the same variable to the same power
17. x-2x+7-9+4x
c. 3x-2
18. -4(3a-5). You would multiply -4 by 3 a, and -4 by -5. It turns to
-4(3a)-4(-5)
a. -12a+20
You need to use the distance formula
so the distance between points (5,-2) and (-3,8) is
which won't simplify so it stays as is
