It took a sled dog team 8.5 hours to travel 161.5 kilometers. What was the average of the sled dog team in kilometers per hour

Llll answer this an i will mark u brainliest

damaskus [11]

2 / -18 and 4/ a (1/2 ) I THINKKK

3 0

3 years ago

Assume, for the sake of this question, that the data were collected through a well-designed, well-implemented random sampling me

amid [387]

Answer:

Since the pvalue of the test is 0.2743 > 0.1, the threshold probably was met.

Step-by-step explanation:

The widget manufacturing company had established a threshold of 60% preferring the proposed new widget to move forward with producing the new widgets.

This means that at the null hypothesis we test if the proportion is at least 60%, that is:

$H_{0}: p \geq 0.6$

And the alternate hypothesis is:

$H_{a}: p < 0.6$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that:

$\mu = 0.6$

$\sigma = \sqrt{0.6*0.4}$

Three hundred thirty-eight of 575 respondents reported preferring the proposed new widget.

This means that $n = 575, X = \frac{338}{575} = 0.5878$

Value of the test-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.5878 - 0.6}{\frac{\sqrt{0.6*0.4}}{\sqrt{575}}}$

$z = -0.6$

Pvalue of the test and decision:

We want to find the probability of a proportion of 0.5878 or lower, which is the pvalue of z = -0.6.

Looking at the z-table, z = -0.6 has a pvalue of 0.2743.

Since 0.2743 > 0.1, the threshold probably was met.

3 0

3 years ago

Solve the system using elimination.

KIM [24]

We can't eliminate as is so we have to change something up there in the equations to get either the x values the same number but opposite signs, or the y values the same number but opposite signs. I chose to change the y values to the same number but different signs. In the first equation y is -3y and in the second one, y is -8y. The LCM of both of those numbers is 24, so we will multiply the first equation by an 8 (8*3=24) and the second equation by 3 (3*8=24) but since they are both negative right now, one of those multiplications has to involve a negative because - * - = +. Set it up like this:
8(-10x - 3y = -18)
-3(-7x - 8y = 11)
Multiply both of those all the way through to get new equations:
-80x - 24y = -144
21x +24y = -33
Now the y's cancel each other out leaving only the x's:
-59x = -177 and x = 3. Now plug that 3 into either one of the original equations to find the y value. Either equation will work; you'll get the same answer using either one. Promise. -7(3) - 8y = 11 gives a y value of -4. so your solution is (3, -4) or B above.

7 0

3 years ago

Read 2 more answers

HELP! HELP!

alexgriva [62]

Answer:

The answer should be C. By combining like terms you can find the answer. 1.75a+2.75a = 4.5a

2.25b + 1.75b = 4b

2.25c + 1.25c = 3.5c

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write an equation perpendicular to x-3y=3 passes through (5,-9)

kherson [118]

3y=x-3
y=1/3x-1
Perpendicular slope: -3
y=-3x+b
Plug in the coordinates in the equation:
-9=-3(5)+b
-9=-15+b
4=b
Equation: y=-3x+4
Also, when finding the perpendicular slope you take the reciprocal of the original slope and make it negative if it is positive and make it positive if it’s negative.

8 0

3 years ago