Answer:
Step-by-step explanation:
Answer:
<em>Answer: C. 32 cm</em>
Step-by-step explanation:
<u>Triangle Inequality Theorem
</u>
Let y and z be two of the side lengths of a triangle. The length of the third side x cannot be any number. It must satisfy all the following restrictions:
x + y > z
x + z > y
y + z > x
Combining the above inequalities, and provided y>z, the third size must satisfy:
y - z < x < y + z
We know the triangle has two congruent angles, which means the triangle is isosceles, i.e., it has two congruent sides.
We are given two side lengths of 16 cm and 32 cm. The third side must have a length of 16 cm or 32 cm for the triangle to be isosceles.
If the third side had a length of 16 cm then the lengths would be 16-16-32. But that combination cannot form a triangle because of the condition stated above.
If y=16, z=16, and x=32 (the worst possible combination), then the inequality
0 < x < 32
wouldn't be satisfied, thus the third side cannot have a length of 16 cm and it must have a length of 32 cm
Answer: C. 32 cm
The answer is 300 or 3*10^2
Answer:
see explanation
Step-by-step explanation:
The sum of the interior angles of a polygon is
sum = 180° (n - 2) ← n is the number of sides
The polygon here has 8 sides, that is n = 8, thus
sum = 180° × 6 = 1080°
Sum the given angles and equate to 1080, that is
14x + 133 + 167 + 138 + 18x + 115 + 151 + 120 = 1080
32x + 824 = 1080 ( subtract 824 from both sides )
32x = 256 ( divide both sides by 32 )
x = 8
Thus the 2 unknown angles are
14x = 14 × 8 = 112°
18x = 18 × 8 = 144°
Answer:
a₁ = -5, d = 7, a₂ = 2, a₃ = 9, a₄ = 16
equation of sequence: 
Step-by-step explanation:
a₁ + a₂ + a₃ = 6
a₁ + a₁ + d + a₁ + 2d = 6
3a₁ + 3d = 6
a₁ + d= 2 ⇒ a₁ = 2 - d
a₄ = 16
a₁ + 3d = 16
2 - r + 3d = 16
2d = 14
d = 7
a₁ = 2-7 = -5
a₁ = -5, d = 7 ⇒ a₂ = -5+7 = 2, a₃ = 2+7 = 9, a₄ = 9+7 = 16
equation of arithmetic sequence:
