Which expression is equivalent to the given expression?
2 answers:
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If a marble is randomly selected from the box, then the probability
that it is small or green is 0.7297
Step-by-step explanation:
A box contains 19 large marbles and 18 small marbles
Each marble is either green or white
9 of the large marbles are green, and 8 of the small marbles are white
If a marble is randomly selected from the box, we need to find the
probability that it is small or green
1. Find P(small) ⇒ P(s)
2.Find P(green) ⇒ P(g)
3. Find P(small and green) ⇒ P(s and g)
4. Use the rule P(small or green) = P(s) + P(g) - P(s and g)
∵ The box contains 19 large marbles and 18 small marbles
∴ The total number of marbles = 19 + 18 = 37
∴ P(s) =
∵ There are 8 small white marbles
∵ There are 18 small marbles
∴ The number of small green marbles = 18 - 8 = 10
∴ P(s and g) =
∵ There are 9 large green marbles
∵ There are 10 small green marbles
∴ The number of green marbles = 9 + 10 = 19
∴ P(g) =
∵ P(small or green) = P(s) + P(g) - P(s and g)
∴ P(small or green) =
∴ P(small or green) = = 0.7297
If a marble is randomly selected from the box, then the probability
that it is small or green is 0.7297
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Answer:
<u>Linear relationship</u>: increasing or decreasing one variable will cause a corresponding increase or decrease in the other variable.
<u>Inverse relationship</u>: the value of one variable decreases as the value of the other variable increases.
<u>Exponential relationship</u>: a constant change in the independent variable (x) gives the same proportional change in the dependent variable (y)
<u>Question 5</u>
As the x-value increases (by one unit), the y-value decreases.
Therefore, this is an inverse relationship.
The y-values are calculated by dividing 35 by the x-value.
**I believe there is a typing error in the table and that the y-value of x = 3 should be 11.67**
<u>Question 6</u>
As the x-value increases, the y-value increases. The y-value increases by a factor of 5 for each x-value increase of 1 unit.
Therefore, this is an exponential relationship.