So, f[x] = 1/4x^2 - 1/2Ln(x)
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
Out of 15 marbles, 3 are yellow, which leaves 12 more marbles that are NOT yellow. 12/15 would be your answer
hope this helps
24:16 which is simplified by dividing both sides by 8 so it becomes:
3:2
Hope this helps :)
Answer:
0.1507 or 15.07%.
Step-by-step explanation:
We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.
First of all, we will find z-scores for data points using z-score formula.
, where,
z = z-score,
x = Sample score,
= Mean,
= Standard deviation.



Let us find z-score of data point 22.03.



Using probability formula
, we will get:

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.
The perimeter of a square is the sum of its sides and they
are all equal, so to obtain the length of each of them we divide the perimeter
of the first fence between 4:
P1= 64 feet/4 sides
P1= 16 feet
Then, the length of each side of the second fence will
increase 2 feet at each end, as shown in the figure. We have then that the
perimeter of the second fence is:
P2 = 20 feet x 4 sides
P2 = 80 feet
The sum of the perimeters of both fences is:
PT = P1 + P2
PT = 64 feet + 80 feet
PT = 144 feet
Total cost = 1.17 $ x 144 feet
Total cost = 168.48 $
The total cost of the fences was $ 168.48