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Schach [20]
3 years ago
13

Help asap thank you so much

Mathematics
1 answer:
gregori [183]3 years ago
7 0

Answer:

C. 25 square inches

Step-by-step explanation:

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Y = (1/4)x^2 - (1/2)lnx..over the interval (1, 7e) ...what is the arc length ?
xenn [34]
So, f[x] = 1/4x^2 - 1/2Ln(x) 
<span>thus f'[x] = 1/4*2x - 1/2*(1/x) = x/2 - 1/2x </span>
<span>thus f'[x]^2 = (x^2)/4 - 2*(x/2)*(1/2x) + 1/(4x^2) = (x^2)/4 - 1/2 + 1/(4x^2) </span>
<span>thus f'[x]^2 + 1 = (x^2)/4 + 1/2 + 1/(4x^2) = (x/2 + 1/2x)^2 </span>
<span>thus Sqrt[...] = (x/2 + 1/2x) </span>
6 0
3 years ago
Help on the 2 one please!!
BARSIC [14]
Out of 15 marbles, 3 are yellow, which leaves 12 more marbles that are NOT yellow. 12/15 would be your answer

hope this helps
7 0
3 years ago
Read 2 more answers
24cm long 16cm wide whars the ratio
Andrej [43]
24:16 which is simplified by dividing both sides by 8 so it becomes:
3:2

Hope this helps :)
3 0
3 years ago
The manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .
Misha Larkins [42]

Answer:

0.1507 or 15.07%.

Step-by-step explanation:

We have been given that the manufacturing of a ball bearing is normally distributed with a mean diameter of 22 millimeters and a standard deviation of .016 millimeters. To be acceptable the diameter needs to be between 21.97 and 22.03 millimeters.

First of all, we will find z-scores for data points using z-score formula.

z=\frac{x-\mu}{\sigma}, where,

z = z-score,

x = Sample score,

\mu = Mean,

\sigma = Standard deviation.

z=\frac{21.97-22}{0.016}

z=\frac{-0.03}{0.016}

z=-0.1875

Let us find z-score of data point 22.03.

z=\frac{22.03-22}{0.016}

z=\frac{0.03}{0.016}

z=0.1875

Using probability formula P(a, we will get:

P(-0.1875

P(-0.1875  

P(-0.1875

Therefore, the probability that a randomly selected ball bearing will be acceptable is 0.1507 or 15.07%.

6 0
4 years ago
A garden is in the shape of a square with a perimeter of
ElenaW [278]

The perimeter of a square is the sum of its sides and they are all equal, so to obtain the length of each of them we divide the perimeter of the first fence between 4:

 P1= 64 feet/4 sides

 P1= 16 feet

 Then, the length of each side of the second fence will increase 2 feet at each end, as shown in the figure. We have then that the perimeter of the second fence is:

 P2 = 20 feet x 4 sides

 P2 = 80 feet

 The sum of the perimeters of both fences is:

 PT = P1 + P2

 PT = 64 feet + 80 feet

 PT = 144 feet

 Total cost = 1.17 $ x 144 feet

 Total cost = 168.48 $

 The total cost of the fences was $ 168.48

6 0
3 years ago
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