A point P has coordinates (–5, 4). What are its new coordinates after reflecting point P over the x-axis?
1 answer:
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Answer:
y = 2(x - 2)² + 3 vertex form
y = 2x² - 8x + 11 standard form
Step-by-step explanation:
Vertex form
y = a(x - h)² + k
(h, k) = (2, 3)
y = a(x - 2)² + 3
To find "a" plug in the y-intercept (0, 11)
11 = a(-2)² + 3
11 = 4a + 3
Subtract 3 from both sides
8 = 4a
a = 2
y = 2(x - 2)² + 3
Expand
y = 2(x² - 4x + 4) + 3
y = 2x² - 8x + 11
