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Vanyuwa [196]
3 years ago
6

All about simulitious equations​

Mathematics
1 answer:
Korolek [52]3 years ago
5 0

Answer:

On occasions you will come across two or more unknown quantities, and two or more equations

relating them. These are called simultaneous equations and when asked to solve them you

must find values of the unknowns which satisfy all the given equations at the same time.

Step-by-step explanation:

1. The solution of a pair of simultaneous equations

The solution of the pair of simultaneous equations

3x + 2y = 36, and 5x + 4y = 64

is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides

to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.

2. Solving a pair of simultaneous equations

There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a

single equation which involves the other unknown. The method is best illustrated by example.

Example

Solve the simultaneous equations 3x + 2y = 36 (1)

5x + 4y = 64 (2) .

Solution

Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation

6x + 4y = 72 (3)

Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:

6x + 4y = 72 − (3)

5x + 4y = 64 (2)

x + 0y = 8

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Step-by-step explanation:

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3 years ago
Which of the following expressions have a value of 180 when b=4?​
vladimir2022 [97]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
4. Simplify the expression. (6 points)
Lunna [17]

<span>4. Simplify the expression.
sine of x to the second power minus one divided by cosine of negative x</span>

<span>(1−sin2(x))/(sin(x)−csc(x))<span>

</span>sin2x+cos2x=1</span> <span>1−sin2x=cos2x<span>

</span>cos2(x)/(sin(x)−csc(x))</span> <span>csc(x)=1/sin(x)</span> <span>cos2(x)/(sin(x)− 1/sin(x))= cos2(x)/((sin2(x)− 1)/sin(x))</span> <span>sin2(x)− 1=-cos2(x)</span> <span>cos2(x)/(( -cos2(x))/sin(x))
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<span>the answer is the letter a) -sin x

</span><span>5. Find all solutions in the interval [0, 2π). (6 points)
sin2x + sin x = 0
</span> using a graphical tool  
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3 0
3 years ago
Read 2 more answers
What is this Divide : (6/7) / (14/12) =
sweet [91]
Use a calculator duh
6 0
2 years ago
I need help with these please :) I suck at math
nikitadnepr [17]
1)
you have similar triangles(ABC, ADE), so their side length ratios are equal

8/2=4/CE
CE*4=4
CE=1


2)
angle bisector theorem:
CD/DA=BC/BA

CD/DA=10/8
I:AD=10CD/8

we also know AC=AD+CD=6
II:CD=6-AD

insert II in I:

AD=10(6-AD)/8
=5(6-AD)/4
=(30-5AD)/4
4AD=30-5AD
9AD=30
3AD=10
AD=10/3
8 0
3 years ago
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