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3 years ago

13

5 friends are going on a 3 kilometer hike. Each person is going to lead the group for an equal distance of their hike. How many

kilometers should each person lead?

1 answer:

kykrilka [37]3 years ago

6 0

Answer:

0.6 km

Step-by-step explanation:

(3 km)/(5 friends) = 0.6 km/friend

Each person should lead for 0.6 km.

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2. The radius of a circle is 7cms. The angle subtended by an arc of the circle at centre is 45º. Find the area of sector.

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19.2cm²

Step-by-step explanation:

Given parameters:

Radius of the circle = 7cm

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Unknown:

Area of the sector = ?

Solution:

To find the area of the sector, use the expression below;

Area of sector = $\frac{Angle of the arc}{360} x \pi r^{2}$

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2 years ago

What is the LCM of 13/16a^3b^3, 11/30a^5b

vichka [17]

Answer:

The L.C.M of given numbers is $\frac{143}{240}a^5b^3$ .

Step-by-step explanation:

The given expressions are

$\frac{13}{16}a^3b^3$

$\frac{11}{30}a^5b$

The factors of given expressions are

$\frac{13}{16}a^3b^3=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b$

$\frac{11}{30}a^5b=\frac{11}{15}\times \frac{1}{2}\times a\times a\times a\times a\times a\times b$

$L.C.M.=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b\times \frac{11}{15}\times a\times a$

$L.C.M.=\frac{143}{240}\times a^5\times b^3$

$L.C.M.=\frac{143}{240}a^5b^3$

Therefore, the L.C.M of given numbers is $\frac{143}{240}a^5b^3$ .

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2 years ago

The sixth grade has collected $116.75 for local animal shelter. Their goal is to collect $500. They have 3 weeks left. How much

DochEvi [55]

Answer:

$127.75 a week

Step-by-step explanation:

first you subtract 116.75 from 500 so you get 383.25

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2 years ago