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4 years ago

True or false? i need help asap

Mathematics

1 answer:

lbvjy [14]4 years ago

8 0

One true
second true
third false
fourth truth
fith false

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Need help and NO LINKS!!! Special Right Triangles (Radical Answers)

Nata [24]

Answer:

x = $5\sqrt{2}$

Step-by-step explanation:

We know that;

The triangle is isosceles, and the hypotenuse is x, the un-labeled side is 5.

Therefore we can say;

5² + 5² = x²

25 + 25 = x²

50 = x²

$\sqrt{50}$ = x

We can simplify this further;

$\sqrt{25} * \sqrt{2}$ = $\sqrt{50}$

$5\sqrt{2}$ = $\sqrt{50}$

Hope this helps!

8 0

3 years ago

Solve the math problem

vfiekz [6]

Answer:

Oof

Step-by-step explanation:

5 0

3 years ago

If line a is parallel to line c, and line c is parallel to line f, and lines c and f are different lines, which of the following

Citrus2011 [14]

Line a is parallel to line f

5 0

4 years ago

Read 2 more answers

Lily and Elsa are both college students.Before mom gave them this months allowance lily had $750 and Elsa had &215.After mom

alina1380 [7]

Mom gave $ 320 to each girl

Solution:

Given that Lily and Elsa are both college students

Before mom gave them this months allowance lily had $750 and Elsa had &215

So amount with Lily and Elsa already is:

amount with Lily = $ 750

amount with Elsa = $ 215

After mom gave each girl an equal amount of money for this months allowance, lily had twice as much money as Elsa

Let "a" be the equal amount of money which mom gave to Lily and Elsa

So now amount with Lily and Elsa after mom gave equal amount is:

amount with Lily = amount with Lily already + a

amount with Lily = 750 + a

amount with Elsa = amount with Elsa already + a

amount with Elsa = 215 + a

Now given that lily had twice as much money as Elsa

Amount with lily = 2(amount with elsa)

750 + a = 2(215 + a)

750 + a = 430 + 2a

2a - a = 750 - 430

a = 320

Thus mom gave $ 320 to each girl

8 0

3 years ago

Unit 8: Right Triangles & Trigonometry Homework 2: Special Right Triangles

Vsevolod [243]

Answer:

Part 1) $x=14\sqrt{2}\ units$

Part 2) $y=14\ units$

Part 3) $z=14\sqrt{3}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ABC

we know that

The triangle ABC is a $45^o-90^o-45^o$

Is an isosceles right triangle

The legs are equal

therefore

AC=AB

$x=14\sqrt{2}\ units$

step 2

Find the length side BC

Applying the Pythagorean Theorem]

$BC^2=AB^2+AC^2$

$BC^2=(14\sqrt{2})^2+(14\sqrt{2})^2$

$BC^2=784\\BC=28\ units$

step 3

Find the value of y

In the right triangle BCD

$sin(30^o)=\frac{BD}{BC}$ ----> by SOH (opposite side divided by the hypotenuse)

$sin(30^o)=\frac{y}{28}$

Remember that

$sin(30^o)=\frac{1}{2}$

$\frac{y}{28}=\frac{1}{2}\\\\y=14\ units$

step 4

Find the value of z

In the right triangle BCD

$cos(30^o)=\frac{DC}{BC}$ ----> by CAH (adjacent side divided by the hypotenuse)

$cos(30^o)=\frac{z}{28}$

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{z}{28}=\frac{\sqrt{3}}{2}\\z=14\sqrt{3}\ units$

3 0

3 years ago

Read 2 more answers