Write a quadratic function f whose zeros are 3 and -10. f(x) =
1 answer:
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SEE ATTACHED IMAGE TO OBSERVE THE GRAPH OF THE FUNCTION.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
For this case, the first thing we should see are the cut points with the x axis.
We note that the graph cuts to the x-axis at x = -2
Therefore, x = -2 is the real solution to the polynomial.
Also this function:
x3 + 6x2 + 12x + 8
It can be rewritten as:
(x + 2) ^ 3
From where we conclude that its roots are:
x = -2 (with multiplicity 3)
Answer:
the equation x3 + 6x2 + 12x + 8 = 0 have:
x = -2
As a real solution with multiplicity 3.
Answer:
r = 8
Step-by-step explanation:
The common ratio r of a geometric sequence is
r = =
= ..... =
Then
r = =
= 8