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melamori03 [73]
3 years ago
9

A scatter plot of data comparing the number of years since Holbrook High

Mathematics
1 answer:
kondor19780726 [428]3 years ago
3 0

y=\frac{23}{5} x+\frac{26}{5}

Step-by-step explanation:

Slope intercept form of an equation is written as;

y=mx+b where m is the slope of the line and b is the y-intercept

Given points (3,19) and (8,42) find m as;

m=Δy/Δx

Δy=42-19=23

Δx=8-3=5

m=23/5

Finding the equation of the line where m=23/5, point (3,19) and (x,y)

m=Δy/Δx

23/5=y-19/x-3

cross product

23(x-3) = 5(y-19)

23x-69=5y-95

23x=5y-95+69

23x=5y-26

23x+26=5y

23x/5 +26/5 =5y/5

23/5 x +26/5 =y

⇒⇒   y=23/5x +26/5

Learn More

Slope-intercept form of an equation :brainly.com/question/12005129

Keywords :scatter plot, data, years, line of fit, points

#LearnwithBrainly

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P= -24<br>q= 12<br>r= -6<br><br>a. (pxq):(q+r)<br>b. (pxr):(r-q)<br><br>what the answer?​
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Step-by-step explanation:

a. ( p × q ) ( q + r )

= ( -24 × 12 ) ( 12 + -6 )

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= 5184

b. ( p × r ) ( r - q )

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5 0
3 years ago
The mean of 10 values is 19. If further 5 values are
Leokris [45]

Answer:

22

Step-by-step explanation:

Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j

Pretend the addition 5 values is k,l,m,n,o

So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20

So the sum of all 15 data is  a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300                since 15(20)=300

Now let's look at the first 10:  We have their mean so we can write:

(a+b+c+d+e+f+g+h+i+j)/10=19

so a+b+c+d+e+f+g+h+i+j=190                               since 10(19)=190

So that means using our first sum equation and our equation sum equation we have

190+k+l+m+n+o=300

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      k+l+m+n+o= 110

So the average of those 5 numbers mentioned in your problem is 110/5=22

3 0
3 years ago
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