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3 years ago

A scatter plot of data comparing the number of years since Holbrook High

Mathematics

1 answer:

kondor19780726 [428]3 years ago

3 0

$y=\frac{23}{5} x+\frac{26}{5}$

Step-by-step explanation:

Slope intercept form of an equation is written as;

y=mx+b where m is the slope of the line and b is the y-intercept

Given points (3,19) and (8,42) find m as;

m=Δy/Δx

Δy=42-19=23

Δx=8-3=5

m=23/5

Finding the equation of the line where m=23/5, point (3,19) and (x,y)

m=Δy/Δx

23/5=y-19/x-3

cross product

23(x-3) = 5(y-19)

23x-69=5y-95

23x=5y-95+69

23x=5y-26

23x+26=5y

23x/5 +26/5 =5y/5

23/5 x +26/5 =y

⇒⇒ y=23/5x +26/5

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Slope-intercept form of an equation :brainly.com/question/12005129

Keywords :scatter plot, data, years, line of fit, points

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umka21 [38]

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

Answer:

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Step-by-step explanation:

Given the expression

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)$

solving the expression

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apply the rule: $a^0=1,\:a\ne \:0$

$=-7+5x^2-x+6-\left(-8x^2+x+3\right)$

$=-7+5x^2-x+6+8x^2-x-3$

simplify

$=13x^2-2x-4$

Therefore, the simplified form is:

$\left(-7x^0+5x^2-x+6\right)-\left(-8x^2+x+3\right)=13x^2-2x-4$

<em>Note: Your answer choices remain a little unclear. But, I have solved the concept and solution, so you can easily figure it out.</em>

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3 years ago

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3 years ago

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just olya [345]

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3 years ago