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Sergio [31]
2 years ago
7

Ashton designs movie sets. For one scene, he has to hang a banner across an archway that takes the shape of a parabola modeled b

y the quadratic equation y = −x2 + 6x. The banner is to be hung at an angle defined by the linear equation y − x = 4, as shown in the figure.
Mathematics
2 answers:
Crazy boy [7]2 years ago
5 0
No question is asked so I'm not sure what you are looking for but below I calculated the point where the two equations intersect:
y - x = 4 → y = x + 4
y = - x² + 6x
x + 4 = - x² + 6x
x² - 5x + 4 = 0
(x - 4)(x - 1) = 0
 x = 4, x = 1

when x = 4, then y = x + 4 = 4 + 4 = 8 → (4,8)
when x = 1, then y = x + 4 = 1 + 4 = 5 → (1,5)

The line and parabola intersect at two points: (4,8) and (1,5)



FromTheMoon [43]2 years ago
4 0

Answer:

The two equations intersect at (1, 5) and (4, 8), so the banner should be hung at these two points.

Step-by-step explanation:

Plato Answer

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If f(x) is a linear function, f(−2)=4, and f(1)=−1, find an equation for f(x)
juin [17]

Answer:

y = -\frac{5}{3}x+\frac{2}{3}

Step-by-step explanation:

Given

f(-2) = 4

f(1) = -1

Required

The equation of the function

The given parameters means that:

(x_1,y_1) = (-2,4)

(x_2,y_2) = (1,-1)

Calculate the slope (m)

m = \frac{y_2 -y_1}{x_2 -x_1}

m = \frac{-1-4}{1--2}

m = \frac{-5}{3}

The equation is then calculated using:

y = m(x - x_1) + y_1

This gives:

y =\frac{-5}{3}(x--2)+4

y =\frac{-5}{3}(x+2)+4

Open bracket

y = -\frac{5}{3}x-\frac{10}{3}+4

Take LCM

y = -\frac{5}{3}x+\frac{-10+12}{3}

y = -\frac{5}{3}x+\frac{2}{3}

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Step-by-step explanation:

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