Answer:
Population of mosquitoes in the area at any time t is:

Step-by-step explanation:
assume population at any time t = P(t)
population increases at a rate proportional to the current population:
⇒dP/dt ∝ P
----(1)
where k is constant rate at which population is doubled
solving (1)

---- (2)
initial population = 400,000
population is doubled every week
⇒P(1)=2P(0)
Using (2)


In presence of predators amount is decreased by 50,000 per day
Then amount decreased per week = 350,000
In this case (1) becomes
---(3)
solving (3) by calculating integrating factor

Multiplying I.F with all terms of (3)

Integrating w.r.to t




at t=0



So, population of mosquitoes in the area at any time t is

Step-by-step explanation:
I had to take help from my brother for the solution as I'm not very good with solid geometry. Hope you got it and thanks for sharing questions like this. It helps me to learn more.
Anything divided by zero is one so the answer is 1
Answer:
<u>76 in²</u>
Step-by-step explanation:
<u>Area of the figure</u>
- Area (top rectangle) + 2 x Area (bottom rectangle)
- 12 x (7 - 2) + 2 x 2 x 4
- 12 x 5 + 16
- 60 + 16
- <u>76 in²</u>